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3 years ago

I will mark Brainliest!!! DO WELL FOR BRAINLIEST PLEASE!

Mathematics

2 answers:

NikAS [45]3 years ago

8 0

Answer:

Isnt it where you write it in the easiest way to understand it? sorry if its wrong :/

Step-by-step explanation:

Mariulka [41]3 years ago

6 0

If you mean standard from in math it is basically writing down a smaller number instead of a larger one. For example 10 x 10 x 10, you could just write 10*3.

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James has $32 and earns $10 per week for his allowance

Leno4ka [110]

The initial value is how much he starts out with, and it says he has $32
So the initial value is B, $32

8 0

3 years ago

Read 2 more answers

1/4d=1/5g(g+e)-h <br> solve for d<br> Please show your work.

loris [4]

Answer:

See below

Step-by-step explanation:

To solve for d, multiply both sides of the equal sign by 4.

4(1/4d) = 4 (1/5g(g+e)-h)

4/4d = 4(1/5 $g^{2}$ + 1/5ge - h)

d = 4/5 $g^{2}$ + 4/5ge - 4h

5 0

3 years ago

Prime factorization of 52

lara [203]

Answer:

The first prime factor we test is 2:

52 / 2 = 26

26 / 2 = 13

13 is a prime number so the prime factorization is

2 * 2 * 13 = 52

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

6d + 7 = 61 what does d equal?

zysi [14]

Answer:

i would reword this to 6x+7=61

Step-by-step explanation:

So.

move the 7 to the right side of the equation but as an opposite number so in this case its gonna be a negative

61-7=54

then you divide the number and get your missing numbers

54/6=9

d=9

plug it in

6(9)+7=61

5 0

3 years ago

Read 2 more answers

A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?

kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

$f(x)=\frac{1}{2^{2x}}$ (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

$\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]$ (2)

To solve this derivative you use the following derivative formula:

$\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}$

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

$\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)$

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

$-2(ln2)2^{-2x}=-1$

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

$-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235$

With this value you calculate f(a):

$f(a)=\frac{1}{2^{2(0.235)}}=0.721$

Next, you use the general equation of line:

$y-y_o=m(x-x_o)$

for xo = a = 0.235 and yo = f(a) = 0.721:

$y-0.721=(-1)(x-0.235)\\\\y=-x+0.956$

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

$0=-x+0.956\\\\x=0.956$

hence, the x-intercept of the tangent line is 0.956

5 0

3 years ago