Answer:
The answer is 10, hope this helps!
Step-by-step explanation:
Answer:
![\frac{-55}{63}](https://tex.z-dn.net/?f=%5Cfrac%7B-55%7D%7B63%7D)
Step-by-step explanation:
![=\frac{2}{21}(\frac{-3}{13})-\frac{7}{9}-\frac{2}{21}(\frac{10}{13})](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%7D%7B21%7D%28%5Cfrac%7B-3%7D%7B13%7D%29-%5Cfrac%7B7%7D%7B9%7D-%5Cfrac%7B2%7D%7B21%7D%28%5Cfrac%7B10%7D%7B13%7D%29)
![=\frac{-2}{91}-\frac{7}{9}-\frac{2}{21}(\frac{10}{13})](https://tex.z-dn.net/?f=%3D%5Cfrac%7B-2%7D%7B91%7D-%5Cfrac%7B7%7D%7B9%7D-%5Cfrac%7B2%7D%7B21%7D%28%5Cfrac%7B10%7D%7B13%7D%29)
![=\frac{-2}{91} +\frac{7}{9} -\frac{2}{21} (\frac{10}{13})](https://tex.z-dn.net/?f=%3D%5Cfrac%7B-2%7D%7B91%7D%20%2B%5Cfrac%7B7%7D%7B9%7D%20-%5Cfrac%7B2%7D%7B21%7D%20%28%5Cfrac%7B10%7D%7B13%7D%29)
![=\frac{-655}{819}-\frac{2}{21} (\frac{10}{13} )](https://tex.z-dn.net/?f=%3D%5Cfrac%7B-655%7D%7B819%7D-%5Cfrac%7B2%7D%7B21%7D%20%28%5Cfrac%7B10%7D%7B13%7D%20%29)
![=\frac{-655}{819}-\frac{20}{273}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B-655%7D%7B819%7D-%5Cfrac%7B20%7D%7B273%7D)
![=\frac{-55}{63}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B-55%7D%7B63%7D)
3y+14=44
Answer: First step is to subtract 14 from each side
3y = 30 (divide each side by 3)
y = 30/3, y = 10
Here, Mass of one specimen = 0.00063 = 6.3 * 10⁻⁴
Now, Mass of 6 specimens = 6.3 * 10⁻⁴ * 6
= 37.8 * 10⁻⁴ = 3.78 * 10⁻³
In short, Your Answer would be: 3.78 * 10⁻³ Kg
Hope this helps!