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emmasim [6.3K]
2 years ago
8

Marshall compared his 8 most recent cell phone bills. They were $102, $97 $98 $102 $98 $104 $95 and 102 what was the mode cost

Mathematics
1 answer:
navik [9.2K]2 years ago
3 0

Answer:

$102

Step-by-step explanation:

The word MODE is a statistical term that refers to the number in a given set of data that occurs the most.

In the above question, we are given the set of data:

$102, $97, $98, $102, $98, $104, $95 and $102

Rearranging, we have:

$95, $97, $98, $98, $102, $102, $102, $104.

The mode cost in the given data set above is the phone cost bill that occurred the most and this is $102.

$102 occurred 3 times in the data set.

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A box contains different colored paper clips. The probability of drawing two red paper clips from the box without replacement is
ivann1987 [24]

Answer: 5/14 which is choice B

================================================

How I got this answer:

Define the following events

A = event of picking a red paper clip on the first selection

B = event of picking a red paper clip on the second drawing

Replacement is not made.

Now onto the probabilities for each

P(A) = 2/5 = 0.4 is given to us as this is simply the probability of picking red on the first try

P(A and B) = probability of both events A and B happeing simultaneously = 1/7

P(B|A) = probability event B occurs, given event A has occured

P(B|A) = probability of selecting red on second selection, given first selection is red (no replacement)

P(B|A) = P(A and B)/P(A)

P(B|A) = (1/7) / (2/5)

P(B|A) = (1/7) * (5/2)

P(B|A) = (1*5)/(7*2)

P(B|A) = 5/14

So if event A happens, then the chances of event B happening is 5/14

------------------

A more concrete example:

If we had 15 paperclips, and 6 of them were red, then

P(A) = (# of red)/(# total) = 6/15 = 2/5

P(B|A) = (# of red left)/(# total left) = (6-1)/(15-1) = 5/14

P(A and B) = P(A)*P(B|A) = (2/5)*(5/14) = 10/70 = 1/7

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