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astraxan [27]
3 years ago
6

Plz help due tomorrow

Mathematics
1 answer:
Tasya [4]3 years ago
8 0

Answer:

2/5y and -0.2y

-6 and -2

Step-by-step explanation:

Here, we want to select the pair of like terms

To do this, we finish the evaluation of the expression

2/5y + 1/5x - 0.2y -6+ (-2)

We have the two y’s together

2/5y and -0.2y

-6 and -2

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Martin's brother just turned 2 years old.What is his brother's age in months?
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24 months. 1 year equals 12 months. 12x2=24
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A drought effects 9 out of 12
masya89 [10]

Answer:

You just have to divide 9 by 12 to get your answer of 75%

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C2 = 39<br><br> (c squared) <br><br> please help :(
iVinArrow [24]

<em>Answer:</em>

<em></em>\boxed{c = \sqrt{39} / c= - \sqrt{39} }<em></em>

<em>This " / " means or, btw!</em>

<em>Step-by-step explanation:</em>

<em></em>c^2 = 39<em></em>

<em>⇒Take square root.</em>

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<em>Hope this helped you!</em>

7 0
3 years ago
I only have a picture so you get a better image
Likurg_2 [28]

Answer:

(15,16)

Step-by-step explanation:

C=halfway between A to B

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A to B on the y axis goes up by 28

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3 years ago
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Suppose that p is the probability that a randomly selected person is left handed. The value (1-p) is the probability that the pe
solmaris [256]

Answer:

a) 1/2

b) 250

Step-by-step explanation:

The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for p such that 1000p(1-p) is maximized. Once we have that p, we can easily find the answer to part b.

Finding the value that maximizes 1000p(1-p) is the same as finding the value that maximizes p(1-p), just on a smaller scale. So, we really want to maximize p(1-p). To do this, we will do a trick called completing the square.

p(1-p)=p-p^2=-p^2+p=-(p^2-p)=-(p^2-p+1/4)-(-1/4)=-(p-1/2)^2+1/4.

Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of p such that the inner part of the square term is equal to 0.

p-1/2=0\\p=1/2.

So, the answer to part a is \boxed{1/2}.

We can then plug 1/2 into the equation for p to find the answer to part b.

1000(1/2)(1-1/2)=1000(1/2)(1/2)=1000*1/4=250.

So, the answer to part b is \boxed{250}.

And we're done!

3 0
2 years ago
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