<span>i Ace</span>hello :
let : A(-6,6) B(6,-2)
the center is w((-6+6)/2 , (6-2)/2)....(midel <span>[ AB]
w(0 ,2)
the ridus is : r = AB/2
AB = </span>√(-6-6)²+(6+2)² = √(144+64) =<span>√208/2
</span>an equation in <span>standard form equation of the circle :
</span>(x+0)²+(y-2)² = (√208/2)²=208/4 = 52
Answer:
-4, 1
Step-by-step explanation:
Answer:
54
Step-by-step explanation:
multiply by 1.8 and add 32
12*1.8=21.6
21.6+32=53.6
53.6 rounded = 54
In order to figure out what N is you have to isolate it by dividing by 50 on both sides as shown below:
Answer:
h(x) = (x +1.5)^2 -20.25
Step-by-step explanation:
We assume you want to rearrange h(x)= x^2 +3x -18.
Recognize the coefficient of x is 3. Add and subtract the square of half that. (3/2)^2 = 9/4 = 2.25
h(x) = (x^2 +3x +2.25) -18 -2.25
Now, write the expression in parentheses as a square, simplify the constant.
h(x) = (x +1.5)^2 -20.25 . . . . . . . . vertex form
