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Zielflug [23.3K]
3 years ago
13

Khan uses 78 feet of fence to make a rectangular pen for his pet rabbit. The length of the pen is 25 feet what is the width of t

he rectangular pen
Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

53 feet

Step-by-step explanation:

78-25=53

Hope this helps :)

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10. rhombus abcd has vertices at a(-2, 7), b(8, 7), c(2, -1), and d (-8, -1).
horrorfan [7]

Answer: 80

Step-by-step explanation:

We can use the formula A=\frac{d_{1}d_{2}}{2}, where d_{1}, d_{2} are the lengths of the diagonals.

By the distance formula,

AC=\sqrt{(-2-2)^{2}+(-1-7)^{2}}=\sqrt{16+64}=4\sqrt{5}\\BD=\sqrt{(-8-8)^{2}+(-1-7)^{2}}=\sqrt{256+64}=8\sqrt{5}

So, the area is \frac{(4\sqrt{5})(8\sqrt{5})}{2}=\boxed{80}

6 0
2 years ago
Airplane is flying at 9000 feet.It begins descending at a rate of 500 feet per minutes write an equation
Hunter-Best [27]

Answer:

9000 - 500m

Step-by-step explanation:

Your original number is 9000. It starts to decrease at a rate of 500 feet per minute. So we know that you will subtract 500 from 9000 but we don't know how many times. Because of this, we will put a variable to represent the minutes that we are descending.

In conclusion: 9000 - 500m

7 0
3 years ago
Blaize is filling a 20,000-gallon swimming pool. If 7040 gallons have already been filled, and the water is entering the pool at
Svetlanka [38]
We can start with subtracting 7040 from 20,000, getting us 12960 gallons remaining, If 720 gallons per hour are coming, we can make the equation 12960 = 720h, with h as hours. Next, we can divide both sides by 720, getting us 18. It will take 18 hours to fill the pool.
3 0
3 years ago
Write the standard equation for the hyperbola with the following conditions: vertices: (-2, -3) and (6, -3) foci: (-4, -3) and (
STALIN [3.7K]
Hello,

Vertices are on a line parallele at ox (y=-3)

The hyperbola is horizontal.

Equation is (x-h)²/a²- (y-k)²/b²=1

Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and  2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)

Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6

c²=a²+b²==>b²=36-4²=20

Equation is:
\boxed{ \dfrac{(x-2)^2}{16} - \dfrac{(y+3)^2}{20} =1}





8 0
3 years ago
4(x + 3) = 3(3x - 1)
LiRa [457]
X=3
have a great day!
4 0
3 years ago
Read 2 more answers
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