Yeah also you got it correct, congrats.
In pure translation or in roll without slip?
In pure translation, just use Fnet = m*a. Fnet = 7.5 Newtons
In roll without slip it has effectively more inertia than 5 kilograms. The effective inertia can be found as:
m_effective = m + I/r^2
For a uniform solid sphere, I = 2/5*m*r^2
So m_effective = 7/5*m
To make a 5 kg bowling ball accelerate at 1.5 m/s^2 in roll without slip, it requires Fnet = 10.5 Newtons, and this ASSUMES that all forces causing the net force on it have lines of action through its center of mass (most common case).
i hope this is what ur looking for
Answer: approximately 0.18
Step-by-step explanation:
Answer:
a = 3
Substitute the value of point (a,7) in the equation and solve for a
5(a)-7=8
5(a)=8+7
5(a)=15
a = 15/5 = 3
God Bless and stay safe!
- Eli <3
The answer is true because they aren't related varables
