Answer:
4, 2, 1, 2, 4
Step-by-step explanation:
-2 <= 0, so use the first equation, f(x) = (1/2)^x, to find f(-2).
f(-2) = (1/2)^-2 = 1^-2/2^-2 = 2^2/1^2 = 4/1 = 4
-1 <= 0, so use the first equation, f(x) = (1/2)^x, to find f(-1).
f(-1) = (1/2)^-1 = 1^-1/2^-1 = 2^1/1^1 = 2/1 = 2
0 <= 0, so use the first equation, f(x) = (1/2)^x, to find f(0).
f(0) = (1/2)^0 = 1^0/2^0 = 1/1 = 1
1 > 0, so use the second equation, f(x) = 2^x, to find f(1).
f(1) = 2^1 = 2
2 > 0, so use the second equation, f(x) = 2^x, to find f(2).
f(2) = 2^2 = 4
27 , he cut 27, pkease give me a brainliest!!
Answer:
dx/dt= 0.2608 at h= 3.1 m
Step-by-step explanation:
a is the length of the ladder. a=5
by pythagorus theorem
![x^2 = a^2-h^2](https://tex.z-dn.net/?f=x%5E2%20%3D%20a%5E2-h%5E2)
differentiating with respect to t we get
......1
The variable h is the height of the ladder's top at time t, and x is the distance from the wall to the ladder's bottom
At h= 3.1
x^2= 6^2-3.1^2 = 9.1×2.9
x= 5.1371 m
given ![\frac{dh}{dt} =-0.4](https://tex.z-dn.net/?f=%5Cfrac%7Bdh%7D%7Bdt%7D%20%3D-0.4)
putting values in 1 to get dx/dt
.
dx/dt= 0.2608 at h= 3.1 m
Answer: Check the attached
Step-by-step explanation: