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Dennis_Churaev [7]
3 years ago
11

Find the nth term for the sequence 1, 4, 9, 16, 25, 36

Mathematics
1 answer:
gayaneshka [121]3 years ago
7 0
1, 4, 9, 16, 25, 36
1+3=4
4+5=9
9+7=16
16+9=25
25+11=36

Evidently, you can notice the pattern. The second number is always increasing by two. Therefore the nth term is n^2.
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Permutations + combination question ^^
BaLLatris [955]

Answer:

Option D is correct

Step-by-step explanation:

Alex has 7 textbooks.

=>The number of ways to place 4 out of 7 books on the shelf is 7P4.

=> Option D is correct

Hope this helps!

6 0
3 years ago
1,000,000,000 meters equal 3 gigameters. True False
alekssr [168]
<span>it is 3000000000 because 1 gigameter is 1000000000 so 3 is 3000000000</span>
5 0
3 years ago
Paula's grades on her history tests this semester are: 79,93, 92, 86, and
Vinvika [58]

Answer:

4.4

Step-by-step explanation:

Data set = 79, 93, 92, 86, 90

Xmean = (79 + 93 + 92 + 86 + 90)/5

= 440/5

Xmean = 88

MAD =

(79 - 88) + (93 - 88) + ( 92 - 88) + ( 86 - 88) + ( 90 - 88)/ 5

=

(9) + (5) + (4) + (2) + (2)/ 5

=

22/5

Mean Absolute Deviation = 4.4

5 0
4 years ago
Read 2 more answers
Helpppppp i need to do this before 10:00 or my teacher said I will fail Ayudarr​
kotykmax [81]

I thing it is “protagonista” not sure tho

3 0
3 years ago
(3 points) Determine whether each of these functions f : {a, b, c, d} → {a, b, c, d} is one-to-one and whether each of these fun
finlep [7]

Answer:

Step-by-step explanation:

Recall the following. Given a function f we say that  

f is one to one if for x,y in the domain of f and f(x)=f(y) then x=y.

This means that there are no different elements in the domain of the function  that are linked to the same value.

f is onto if for every y in the codomain of f, then there is an element x in the domain of f such that f(x) = y. That is, given an element y in the codomain of f, there exists and element in the domain that is linked to y.

a)  

f(a) =b, f(b)=a, f(c) = c, f(d) = d. Note that this function links each element in {a,b,c,d} to different elements in {a,b,c,d}, so it is a one to one function. Since for every element x in {a,b,c,d} there is an element y in {a,b,c,d} such that f(y) = x, then this function is also onto.  

b)  

f(a)=b, f(b) = b, f(c) = d, f(d) = c. Note that the elements a,b are linked both to b, so this function fails to be one-to-one. Also, note that the element a has no element x in {a,b,c,d} such that f(x) = a, so this function fails to be onto.  

c)  

f(a) = d, f(b) = b, f(c) = c, f(d) = d.  

As in b), since a and d are linked to d, then this function is not one to one. Also, since the element a has no element x in {a,b,c,d} such that f(x) = a, then it also fails to be onto.  

8 0
3 years ago
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