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3241004551 [841]
2 years ago
6

Pran ran 29 miles less than Robin last week. Pran ran 19 miles. How many miles did Robin run?

Mathematics
1 answer:
9966 [12]2 years ago
5 0
Pran= 19
Robin= 29+19

29+19= 48
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What is the value of x?
lorasvet [3.4K]

Answer:

x=9

Step-by-step explanation:

We can use similar triangles and ratios.  Put the small triangle side over the large triangle side.

9cm            3x -20

----------   = ----------------    We need to add the sides to get to the larger triangle

72+9 cm   3x-20 + 56


We can cross multiply to solve

9 * (3x-20+56) = (72+9) * (3x-20)

Simplify

9*(3x+36) = 81*(3x-20)

Distribute

27x +324 = 243x -1620

Subtract 27x from each side

27x-27x +324 = 243x-27x -1620

324 = 216x-1620

Add 1620 to each side

324+1620 = 216x

1944 = 216x

Divide each side by 216

1944/216 = 216x/216

9=x

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3 years ago
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Point M is the midpoint of segment AB. If AM = 50 – 3x and MB = –20 + 4x, find the value of AM
love history [14]
The answer to your question is 20
4 0
2 years ago
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A local company rents a moving truck for $750 plus $0.59 per mile driven over 1000 mi. What is the maximum number of miles the t
Katen [24]

The maximum number of miles the truck can be driven so that the rental cost is at most \$1000 is \boxed{1423{\text{ miles}}}.

Further explanation:

Given:

A local company rents a moving truck for \$ 750.

Rent per mile is \$ 0.59 if the truck moves more than 1000 miles.

Explanation:

The rental cost of the truck is \$ 750 if he drove less than 1000 miles.

{\text{Cost}} = \$ 750{\text{   }}x \leqslant 1000

The rental cost of the truck can be expressed as follows,

{\text{Cost}} = 750 + 0.59x{\text{  }}x > 1000

The rental cost is at most \$1000.

750 + 0.59x \leqslant 1000

The maximum number of miles can be obtained as follows,

\begin{aligned}0.59x &\leqslant 1000 - 750\\0.59x &\leqslant 250\\x &\leqslant \frac{{250}}{{0.59}}\\x &\leqslant 423.7\\\end{aligned}

The maximum number of miles can be obtained as follows,

\begin{aligned}{\text{Maximum miles}} &= 1000 + 423\\&= 1423 \\\end{aligned}

The maximum number of miles the truck can be driven so that the rental cost is at most \$1000 is \boxed{1423{\text{ miles}}}.

Learn more:

  1. Learn more about inverse of the function brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Linear inequality

Keywords: local company, rents, moving, truck, $750, $0.59, maximum, 1000 miles, $1000, at most, at least, number of miles, rental cost, driven over  

3 0
3 years ago
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I need help please ASAP full points
kotegsom [21]

The best way to solve this problem is with a simple equation: part = percent (in decimal form) x whole

In this problem, we're trying to solve for the <em>whole </em>amount that the camera can hold, so we'll assign that the variable w.

We can use the information they gave us - 96 is the <em>part</em>, and 24% is the percent. We'll convert that to decimal form - 0.24

Then, we just plug these values back into the above equation:

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Divide both sides by 0.24 to get w on it's own, and you have your answer!

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Therefore, the memory card can hold up to 400 pictures.


Note: this equation is <em>super </em>helpful. It's good to have on hand for any problem involving percents, because you can solve for the part, percent, or whole depending on the problem.

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2 years ago
Solve for c<br> 4(3+c)+c=c+4
Sonja [21]

Answer:

c = -2

Step-by-step explanation:

Given equation is :

4(3+c)+c=c+4

12 + 4c + c = c + 4

12 + 4c = 4                    [dividing by 4]

3 + c = 1                         [adding and subtracting 3]

c = -2

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3 years ago
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