1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeyben [28]
4 years ago
8

30 PTS!! Can someone PLEASE rephrase this? The compass and straightedge is more important in constructing geometric structures t

han other drawing tools such as rulers and protractors. Because steps taken with a compass and straightedge cannot be seen at first glance and this situation become a problem for students.
Mathematics
1 answer:
jek_recluse [69]4 years ago
5 0

Answer:

Step-by-step explanation:

This study investigated three mathematics teachers' construction process of geometric structures using compass and straightedge. The teacher-student-tool interaction was analysed. The study consists of the use of a compass and straightedge by the teachers, the ideas of the teachers about their use, and the observations regarding the learning process during the construction of the geometric structures. A semi-structured interview was conducted with the teachers about the importance of the use of a compass and straightedge to construct geometric structures. It was found that teachers taught compass and straightedge constructions in a rote manner where learning is little more than steps in a process. The study concludes with some suggestions for the use of a compass and straightedge in mathematics classes based on the research results. SUMMARY Purpose and significance: For more than 2,000 years, the way in which geometric structures could be constructed with the help of compasses and straightedges has caught the attention of mathematicians. Nowadays, mathematics curriculums place an emphasis on the use of the compass and straightedge. The compass and straightedge is more important in constructing geometric structures than other drawing tools such as rulers and protractors. Because steps taken with a compass and straightedge cannot be seen at first glance and this situation become a problem for students. However, 'doing compass and straightedge construction early in the course helps students to understand properties of figures'

You might be interested in
Please help thank you
aivan3 [116]

Answer:

a = 4

b = 11

Step-by-step explanation:

To convert the recurring decimals into fraction we will follow the following process.

Given recurring decimal is 0.36363636....

Let x = 0.363636......... (1)

Multiply this decimal with 100.

100x = 36.36363636...........(2)

Now subtract expression (1) from expression (2)

100x = 36.363636.......

<u>      x =   0.363636.......</u>

99x = 36

x = \frac{36}{99}

x = \frac{4}{11}

Since, x=\frac{a}{b}=\frac{4}{11}

a = 4 and b = 11 will be the answer.

4 0
3 years ago
Find the area of the triangle. <br><br> A. 90m2<br> B. 67.5m2<br> C.45m2<br> D.33m2
sergiy2304 [10]

Answer:

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
Justin's planning to purchase 1 book for $20 each month for 1 year .How much money will he spend on books in that year?
andre [41]
12 months in a year.
$20 a month.

20*12=240

He'd spend 240 dollars.
4 0
4 years ago
Read 2 more answers
Given that f(x) = 2x + 1 and g(x) = the quantity of 3x minus 1, divided by 2 , solve for g(f(3)). (5 points)
BARSIC [14]
The answer to the question

3 0
4 years ago
If the vertex of a parabola is at (2, 3) and the point (0, -1) is also on the parabola, find an equation for the parabola. Write
STALIN [3.7K]

Answer:

y=-1(x-2)^2+3

Step-by-step explanation:

W have been given that the vertex of a parabola is at (2, 3) and the point (0, -1) is also on the parabola. We are asked to find the equation of parabola in the form y=(x-h)^2+k.  

We know that vertex form of parabola in form y=a(x-h)^2+k, where (h,k) in vertex of parabola.  

Upon substituting coordinates of vertex, we will get:

y=a(x-2)^2+3

To find the value of a, we will substitute coordinates of point (0, -1) as:

-1=a(0-2)^2+3

-1=a(4)+3

-1=4a+3

-1-3=4a+3-3

-4=4a

\frac{-4}{4}=\frac{4a}{4}

-1=a

Therefore, our required equation would be y=-1(x-2)^2+3.

3 0
3 years ago
Other questions:
  • Tell what you would do to isolate the variable. -5c = 5/24
    12·2 answers
  • The lines shown below are parallel. If the green line has a slope of
    6·1 answer
  • Maya wants to purchase a yearly membership to an indoor skateboard park. She'll also need to pay a set fee each time she visits
    9·1 answer
  • Solve for x
    5·1 answer
  • Suppose f(x) = x^3. Find the graph of f(x+5)
    11·1 answer
  • (c) Evaluate P P(0). What might this stand for?
    14·1 answer
  • Please help!! Cause I’m not smart
    12·2 answers
  • The enrollment at a community
    13·2 answers
  • Solve using Substitution! <br>y = x + 8 <br>y = 4x – 1​
    11·2 answers
  • What is the LCD of 2/7 and 12/5
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!