Hello!
If we want to find the mean (average) of any set of numbers, all you need to do is add the set together, then divide by how many numbers are in the set.
When we add all the numbers we get: 100
Next we just divide by the number of people which is 10: 100 divided by 10 is 10
So, the mean age of the swimmers on the team is an even number of 10.
Answer is D
After dilation the image remain same but it is stretched or shrinked to the original size.
That means the ratio of the sides and the angles between the sides remain same .
Here we did dilation of ABCD which made it to EFGH.
Hence the ratio of the corresponding sides of the original rectangle ABCD should remain same even after dilation.
the corresponding sides are : AB and EF
BC and FG
CD and GH
DA and HE
* Let us find ratio of the sides AB and BC
given that AB= 10 and BC= 14
AB/BC= 10/14 = 5 /7 ( 10 and 14 both are multiple of 2 so we reduced them by a factor of 2 )
* the raio of the corresponding sides EF and FG should be same ( 5/7)
in the option D EF= 25 and FG= 35
so EF/FG= 25/35 = 5 /7 ( both are multiple of 5 so we reduced them by the factor of 5 )
Since ratio of the corresponding sides are coming out to be same for the EFGH given in option D it should be the dilation of the ABCD
Answer:
Step-by-step explanation:
L1 -x + 2y = -1
L2 5x - 10y = 6
-x + 2y = - 1 multiply by -1
x - 2y = 1 multiply by 5
5x - 10y = 5 is similar that 5x - 10y = 6
The system has no solution
Answer:
<h2>
∠PQT = 72°</h2>
Step-by-step explanation:
According to the diagram shown, ∠OPQ = ∠OQP = 18°. If PQT is a tangent to the circle, it can be inferred that line OQ is perpendicular to line QT. Ths shows that ∠OQT = 90°.
Also from the diagram, ∠OQP + ∠PQT = ∠OQT;
∠PQT = ∠OQT - ∠OQP
Given ∠OQP = 18° and ∠OQT = 90°
∠PQT = 90°-18°
∠PQT = 72°
There is nothing in the space. If there were, then the space would not be blank.
