Answer:
4
Step-by-step explanation:
The values on the left of the table represent the number of fish caught, and the number of the right of the table represents how many family members caught that amount of fish.
Therefore, the first row means that 0 family members caught 0 fish.
The second row means that 3 family members caught 1 fish.
The third row would mean 1 family member caught 2 fish.
The next row would mean 0 family members caught 3 fish.
And the final row would mean 4 family members caught 4 fish.
The question does not ask for the total amount of fish caught; rather is ask for the maximum number of fish that a single family member caught.
Therefore, the maximum amount of fish that a single family member catches is 4. (And 4 family members did so. But individually, the maximum amount of fish one person caught is 4).
Answer:
C
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
D/-9<=-8 multiply both sides by -9
d,=72
