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Romashka [77]
4 years ago
10

Solve for x -3x = -15 A) x = -45 B) x = 5 C) x = -5

Mathematics
1 answer:
Zina [86]4 years ago
6 0

C-x=-5

Step-by-step explanation:

-3x=-15

or,-3x x =-15

or, x=-15÷3

therefore, x=-5

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Complete the function table for each equation y=-3x
Igoryamba

Answer:

<u><em>The answer will vary depending on what table you were given.</em></u>

<u><em></em></u>

Step-by-step explanation:

I'm pretty sure you were given a table along with this question. I do not have this table, so I'm going to create my own. Before I do, I'll explain the function if that's what you're wondering.

Function: y = -3x

This function means you multiply -3 by x to get y.

An example of this is x = 6. To find y, we multiply -3 by 6; y = -18 in this example.

Now, I'll make a small chart with x going from 0 to 5.

|  X |  Y  |

|  0  |  0  |

|  1   |  -3 |

|  2  |  -6 |

|  3  |  -9 |

|  4  |  12 |

|  5  | -15 |

<h2>I hope this helped you understand the question!</h2>
5 0
3 years ago
How many outfits can you get from 5 suits, 7 shirts, 4 ties and 6 hats
Vaselesa [24]

Answer:

840 outfits

Step-by-step explanation:

4 0
4 years ago
Please Help
xxMikexx [17]

Answer:

degree of length = 1

degree of width = 1

degree of height = 3

degree of volume = 4

Step-by-step explanation:

V = (4x - 1)( x)(x³) = (4x² - x)x³ = 4x∧5 - x∧4

dV/dx = 20x∧4 - 4x³  

d²V/dx² = 80x³ - 12x²

80x³ - 12x² = 0

4x²(20x - 3) = 0

20x - 3 = 0

20x = 3

∴ x = 3/20

Length, 4x - 1 = 4 (3/20) - 1 = 3/5 - 1 = -2/5

∴ degree of length = 1

Width, x = 3/20

∴ degree of width = 1

Height, x³ = (3/20)³ = 27/8000

∴ degree of height = 3

Volume, 4x∧5 - x∧4 = 4(3/20)∧5 - (3/20)∧4 = 4(243/3200000) - (81/160000) = 243/800000 - 81/160000 = (243 - 405)/800000 =               - 162/800000 = - 81/400000

∴ degree of volume = 4

5 0
3 years ago
Read 2 more answers
1. Is each of the following a function?
Mashcka [7]
The answer to A is yes
4 0
3 years ago
2x6+8-1 can anyone help?
Lynna [10]

Answer:

the answer is 19

Step-by-step explanation:

3 0
3 years ago
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