MN is the mid-line of a trapezoid HJLK.<span>
The length of the mid-line of a trapezoid is half of the sum of the lengths of its bases </span>⇒
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(KL + HJ)/2 = MN
(KL + 45)/2 = 28
KL + 45 = 28 * 2
KL + 45 = 56
KL = 56 - 45
KL = 11
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Answer:
<em>Graph below</em>
Step-by-step explanation:
<u>Transformations</u>
Triangle ABC has coordinates A=(-4,2) B=(-2,6) C=(3,2)
We'll use the transformation (x,y) -> (2x, y+3) to map it to the triangle A'B'C'. Let's calculate the coordinates:
A'=(-8,5)
B'=(-4,9)
C'=(6,5)
The image below shows both triangles in the same grid
What ever solution is left over after solved
Answer:
no
Step-by-step explanation:
6x-5x-2x=8-5
-1x=3
-1x/-1=3/-1
x=-3
21+4(32-5)=448
I think it’s 448