All categories

3 years ago

Is it y=x ?? Pls help

Mathematics

1 answer:

DerKrebs [107]3 years ago

3 0

It's the first one. y can equal x as long as y doesn't equal x multiple times. We also know the last two are wrong because they're saying the same thing. A linear function is a straight line.

You might be interested in

What is the equation of the line that passes through the point (2,-2) and has a slope of -1/2?

katrin2010 [14]

Answer:

y = -1/2x - 1

Step-by-step explanation:

We can use the point-slope form of the equation:

y-y1 = m(x-x1)

Where the given y1 = -2, x1 = 2, and m = -1/2. This yields:

y - (-2) = -1/2(x - 2)

y + 2 = -1/2x + 1

y = -1/2x +1 - 2

y = -1/2x - 1

3 0

3 years ago

Given the equation of the line y+3=4/5(x+10) what is the slope

Stells [14]

The slope is 4/5
You would get the equation in y = mx + b form
m (slope) will be the coefficient of x

6 0

3 years ago

An oil tank is leaking into a lake at a rate of 0.1 m3/day. The oil slick forms a semicircular disk whose center is at the leak

gregori [183]

Answer:

17.9 m/s

Step-by-step explanation:

Volume of the slick = 0.5 x π r² h--------------------------------- (1)

Where r = radius of slick

h = thickness of slick, 10⁻⁶m

If 0.5m³ of oil leaked, then the radius of the semicircular slick can be calculated from equation (1)

V = 0.5 x π r² h

0.5= 0.5 x π x r² x 10⁻⁶

r² = 10⁶/ π

r = 10³/√π

dV/dt = πrh dr/dt + 0.5π r² dh/dt----------------------------------- (2)

Asumming the film thickness is constant , equation (2) becomes

dV/dt = πrh dr/dt-------------------------------- (3)

dV/dt = 0.1m³/day

r= 10³/√π

dr/dt= rate of expansion of the slick

Substituting into (3);

0.1 = π x 10³/√π x 10⁻⁶ x dr/dt

dr/dt = 0.1 x 10⁶/ ( π x 10³/√π)

= 17.9479 m/s

≅ 17.9 m/s

8 0

4 years ago

Select the prime number. 30(A) 31(B) 32(C) 33(D)

noname [10]

Answer:

31 as it has only 2 factors which is 1 and 31

7 0

3 years ago

Read 2 more answers

If r(X)=2-x^2 and w(X)=X-2, what is the range of (w*r)(X)

slega [8]

The given function are
r(x) = 2 - x² and w(x) = x - 2
(w*r)(x) can be obtained by multiplying the both function together

So, (w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)
(w*r)(x) = x (2-x²) - 2(2-x²)
= 2x - x³ - 4 + 2x²

∴ (w*r)(x) = -x³ + 2x² + 2x - 4


It is a polynomial function with a domain equal to R

The range of (w*r)(x) can be obtained by graphing the function

To graph (w*r)(x), we need to make a table between x and (w*r)(x)

See the attached figure which represents the table and the graph of (w*r)(x)


As shown in the graph the range of (w*r)(x) is (-∞,∞)

8 0

3 years ago

Read 2 more answers