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Troyanec [42]
3 years ago
15

In the class , 0.48 of the students have brown hair. 3/11 of the students have blonde hair . What percent of students have neith

er brown nor blonde hair ?
Mathematics
1 answer:
garri49 [273]3 years ago
4 0
0.48 = 48%
3/11 = 0.27 = 27%

100% - (48% + 27%) = 
100% - 75% = 25%

ur answer is 25%
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Suppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. Your calculator answer would be 11.76
yKpoI14uk [10]

Answer:

12 cm²

Step-by-step explanation:

Length of rectangle = 5.6 cm

Width of rectangle = 2.1 cm

Area of rectangle = Length of rectangle×Width of rectangle

⇒Area of rectangle = 5.6×2.1

⇒Area of rectangle = 11.76 cm²

11.76 has 4 significant figures in order to write this term in 2 significant terms we round of the term

The last digit in the decimal place is 6. Now, 6≥5 so we round the next digit to 8 we get

11.8

Now the last digit in the decimal place is 8. Now, 8≥5 so we round the next digit to 2 we get

12

∴ Hence the area of the rectangle when rounded to 2 significant figures is 12 cm²

5 0
3 years ago
Look at the figure. If m∠JKM = 48, find m∠J.
vladimir2022 [97]

Answer:

42

Step-by-step explanation:

The measure of angle K is 48, the measure of angle m is 90. From there you have 138 degrees. A triangle is 180 degrees. You subtract 138 from 180.

3 0
3 years ago
Question 5 (1 point)
aleksley [76]

Answer:

A = x^2 + 5x - 14

Step-by-step explanation:

A = L × W

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5 0
3 years ago
What’s (3x86)+(9538+629)
lara [203]

(3x86)+(9,538+629) = 10,425

Hope this helps


5 0
3 years ago
A simple random sample from a population with a normal distribution of 99 body temperatures has xbar = 99.10°F and s = 0.64°F. C
motikmotik

The general formula for the margin of error is e = (zs)/√n, when the sample size is 30 or more (otherwise, we'd need to to a t-interval).

Since we're needing a 99% confidence interval, we need to know what the positive z-score associated with this two-tailed area under the normal curve is.  This can be a little tricky if you're using a standard normal table.  What you want is a two-tailed interval that has an area of .99.  What this means is that the remaining 0.01 is divided into 0.005 on each end.  This then means that, to the right of the mean (which is 0), the area is 0.005 less than the total right-half area of 0.5, or 0.495.  The total cumulative area, then, includes this plus the left half of .5, or 0.5 + 0.495 = .0995.

Then, if all we have to go on is a cumulative standard normal table, then we need to find the area closest to 0.995 and find the corresponding z-score.  This z-score is 2.58.

Now that we have the z-score, we can now plug in all the values into the formula.  

e = (2.58 · 0.66)/√102 = 0.1686.

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The TI-84 method:

This is much easier, if you're allowed to use this technology.  You begin with the STAT button, and then move over to the TESTS menu.  Then select ZInterval.  We have summary stats rather than data in this problem, so we select Stats as the input.  For the standard deviation, we put 0.66, for x-bar 98.8, for n 102, and for C-level 0.99.  Then select Calculate, and it will provide the interval at the top of the screen (98.632, 98.968).  Note that the lower limit is slightly different by this method.  This is because, when doing it by hand, we had to approximate the z-score.  This created a rounding error, albeit  a small one.

4 0
3 years ago
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