Answer:
Elements that are metals tend to lose electrons and become positively charged ions called cations. Elements that are nonmetals tend to gain electrons and become negatively charged ions called anions
Explanation:
Answer:
they both have structures in common and have ribosomes
Explanation:
Answer:
<h2>i) C-1
</h2><h2>ii) C-3
</h2><h2>iii) C-3
</h2><h2>iv) C-2 (methyl group)
</h2><h2>v) C-4
</h2><h2>vi) C-4
</h2><h2>vii) Equally distributed in C-2 and C-3.</h2>
Explanation:
i) In Fructose-1,6-bisphosphate
, initial incorporation of 14^C occurs at C-1
ii) In Glyceraldehyde-3-phosphate, initial incorporation of 14^C occurs at C-3
iii) In Phosphoenolpyruvate, initial incorporation of 14^C occurs at C-3
iv) In Acetyl-CoA, initial incorporation of 14^C occurs at C-2 (methyl group)
v) In Citrate, initial incorporation of 14^C occurs at C-4
vi) In a-ketoglutarate, initial incorporation of 14^C occurs at C-4
vii) in Oxaloacetate, initial incorporation of 14^C occurs at Equally distributed in C-2 and C-3.
Hi,
I think the answer is the third one.
I hope this helps. If you’d like further explanation please let me know. Also, English is not my first language, so I’m sorry for any mistakes.
Answer:
C. 1,024
The answer can be worked out using 2^pairs of chromosomes
Explanation:
Imagine there were <u>two</u> pairs of chromosomes:
- A paired with B
- C paired with D
A gamete could have the following combinations:
Therefore, with two pairs of chromosomes, there are 4 (2²) possibilities
Now, Imagine there were <u>three</u> pairs of chromosomes:
- A paired with B
- C paired with D
- E paired with F
A gamete could have the following combinations:
- A + C + E
- A + D + E
- A + D + F
- A + C + F
- B + D + F
- B + C + F
- B + C + E
- B + D + E
Therefore, with three pairs of chromosomes, there are 4 (2³) possibilities
For 10 chromosomes - there are 2¹⁰ possibilities. 2¹⁰ = 1024
