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just olya [345]
3 years ago
8

Bob is a ringmaster for the circus. He stands inside a circular circus ring that has a diameter of 14 meters. What is the area o

f the ring to the nearest tenth of a square meter?​
Mathematics
1 answer:
Verizon [17]3 years ago
3 0

Answer:

Diameter14

Using the formulas

A=πr2

d=2r

Solving for A

A=1

4πd2=1

4·π·142≈153.93804m²

Step-by-step explanation:

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Use a calculator to solve the following equation for θ on the interval [−90∘,90∘]. Sin(θ)=34
exis [7]

The value of θ from the given equation is 48.59degrees

<h3>Trigonometry identity</h3>

Given the trigonometry function

Sin(θ)=3/4

We are to find the value of theta that will make the expression true

Take the arcsin of both sides

arcsin Sin(θ)= arcsin(3/4)

θ = arcsin(3/4)

θ = 48.59

Hence the value of θ from the given equation is θ = 48.59 defense

Learn more on trig identity here:brainly.com/question/7331447

4 0
2 years ago
Design a sine function with the given properties:
Rom4ik [11]

Answer:

f(x)=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13.

Step-by-step explanation:

Given information:

Period = 24 hr

Maximum = 16 at t=16 hr.

Minimum = 10 at t=4 hr.

The general sin function is

y=A+\sin(B(x-C))+D        .... (1)

where, |A| is altitude, \frac{2\pi}{B} is period, C is phase shift and D is midline.

Period is 24 hr.

24=\dfrac{2\pi}{B}\Rightarrow B=\dfrac{\pi}{12}

Altitude is

A=\dfrac{Maximum-Minimum}{2}=\dfrac{16-10}{2}=3

D=\dfrac{Maximum+Minimum}{2}=\dfrac{16+10}{2}=13

The function is minimum at t=4 and maximum at t=16,phase shift is

C=\dfrac{16+4}{2}=10

Substitute these values in equation (1).

y=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13

Therefore, the required function is f(x)=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13.

8 0
3 years ago
Luis purchased 24 purple plants and 8 pink plants. He wants to plant them in equal groups in his garden. What is the largest num
fiasKO [112]
He can make 8 groups with 1 pink plant and 3 purple plants in each group.
4 0
3 years ago
An acute angle, θ, is in a right triangle such that sin of theta is equal to 3 over 8 period What is the value of cot θ?
Serggg [28]

We want to find the value of cot(θ) given that sin(θ) = 3/8 and θ is an angle in a right triangle, we will get:

cot(θ) = (√55)/3

So we know that θ is an acute angle in a right triangle, and we get:

sin(θ) = 3/8

Remember that:

  • sin(θ) = (opposite cathetus)/(hypotenuse)
  • hypotenuse = √(  (opposite cathetus)^2 +  (adjacent cathetus)^2)

Then we have:

opposite cathetus = 3

hypotenuse = 8 = √(3^2 +  (adjacent cathetus)^2)

Now we can solve this for the adjacent cathetus, so we get:

adjacent cathetus = √(8^2 - 3^2) = √55

And we know that:

cot(θ) = (adjacent cathetus)/(opposite cathetus)

Then we get:

cot(θ) = (√55)/3

If you want to learn more, you can read:

brainly.com/question/15345177

8 0
3 years ago
A regular polygon has a perimeter of 40 cm and a apothem of 6 cm. find the polygons area
Anestetic [448]

Answer:

a = 120 cm²

Step-by-step explanation:

n = number of sides

edge length

40/n

divide the polygon into n congruent triangles

a = (1/2)(edge * apothem) * number of triangles

a = (1/2)(40/n)(6) * n

n cancels out

a = (1/2)(40)(6)

a = 120 cm²

3 0
3 years ago
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