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4 years ago

A plane flew a total of 2,220 miles. Its average speed was 555 miles per hour. How many hours did the plane fly?

1 answer:

7 0

Ok. I will put my explanation in the answer box because apparently it's not good enough in the comments.

2220 divided by 555 is 4.
We do this equation because we need to find out how many 555 miles go into 2220 miles. The answer is 4, which we need to convert to hours, so it is 4 hours.
1 hour is 555 miles
2 hours are 1110 miles.
3 hours are 1665 miles.
4 hours are 2220 miles which is what we need.

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Forth grade math: What happens to the area of the triangle when one of the dimensions is doubled and halved?

Alja [10]

$\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ b=\stackrel{doubled}{2b} \end{cases}\implies A=\cfrac{1}{2}(2b)(h)\implies \stackrel{\textit{twice as the original area}}{A=bh} \\\\[-0.35em] ~\dotfill$

$\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ h=\stackrel{halved}{\frac{h}{2}} \end{cases}\implies A=\cfrac{1}{2}b\left( \cfrac{h}{2} \right)\implies \stackrel{\textit{half of the original area}}{A=\cfrac{1}{2}bh\left( \cfrac{1}{2} \right)}$

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4 years ago

Use the data to find the lower quartile value.

grandymaker [24]

Answer:$9.75

Step-by-step explanation:

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4 years ago

What is the radical expression that is equivalent to the expression 27 1/5? Enter your answer as a radical. For example, if your

yuradex [85]

Answer:

$27^{\frac{1}{5} }=\sqrt[5]{3^3}$

Step-by-step explanation:

we are given

$27^{\frac{1}{5} }$

we can use rule to change exponent into radical

$\sqrt[n]{a} =a^{\frac{1}{n} }$

so, we can write as

$27^{\frac{1}{5}}=(3\times 3\times 3)^{\frac{1}{5}}$

$27^{\frac{1}{5}}=(3^3)^{\frac{1}{5}}$

now, we can use rule

and we can write our term as

$27^{\frac{1}{5} }=\sqrt[5]{3^3}$

5 0

3 years ago

Read 2 more answers

What does a triangle with the measures 20,60, and 100 degrees look like?

irinina [24]

This most of the angles you asked about except for 20 i m not sure about it sorry

6 0

4 years ago

Geometry problem: Find the distance between the parallel lines y=-3/2x+1 and 2y+3x=10

s344n2d4d5 [400]

Answer:

d = 1.847

Step-by-step explanation:

To avoid any ambiguity, please enclose the slope -3/2 inside parentheses:

y = (-3/2)x + 1. Next, solve the 2nd equation for y: 2y = - 3x + 10 => y = (-3/2)x + 5. Notice how these two lines have the same slope (-3/2)? Thus, the two given lines are parallel.

It's important to realize that the distance between these two lines is a line segment with perpendicular to both lines. Thus, the segment representing this distance has the form y = (2/3)x + c. Let's say that this segment passes through the y-intercept of y = (-3/2)x + 1; it thus passes through (0,1), and thus has the equation y = (2/3)x + 1.

Find the point at which this y = (2/3)x + 1 intersects the line y = (3/2)x + 5. Note that the xresultant point

Setting these two equations = to one another results in (2/3)x + 1 = (-3/2)x + 5.

Multiplying both sides by the LCD (6) will eliminate the fractions:

4x + 6 = -9x + 30. Combining like terms: 13x = 24, and x = 24/13 = 1.846.

Substitute this x-value into y = (2/3)x + 1 to find the y-coordinate of the point of intersection of y = (2/3)x + 1 and y = (-3/2)x + 5:

When x = 1.846, y = (2/3)(1.846) + 1 = 1.231.

Thus, the desired distance is that between (0,1) and (1.846, 1.231), and is:

d = √ [ (1.846 - 0)^2 + (1.231 - 1)^2 ] = √ [ (1.846)^2 + (0.053)^2 ]

This simplifies to d = √ [ 3.408 + 0.003 ] = √3.411, or

d = 1.847 (answer)

7 0

3 years ago