Answer:
i hope that helps......
Three customers open a bank account that does not earn interest with first bank. The table below displays the amount each custom
er deposits and the frequency of deposits. at the end of three years, which customer has saved the most money?
1 answer:
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*see attachment below for the box plots that is being referred to
Answer:
*The median weight for shelter A is greater than that for shelter B
*The data for shelter B are a symmetric data set
Step-by-step explanation:
Let's take each stated option and examine the box plot to see which is TRUE or NOT.
OPTION 1: "The median weight for shelter A is greater than that for shelter B."
The median for shelter A = 21,
Median for shelter B = 18
Median weight for shelter A (21) is greater than that for shelter B.
This statement in this option is TRUE.
OPTION 2: "The median weight for shelter B is greater than that for shelter A."
Median for B (18) < median of A (21)
This statement in option is NOT TRUE.
OPTION 3: "The data for shelter A are a symmetric data set."
This is NOT TRUE because the length of both whiskers are unequal and also, the box is not divided equally. One side is longer than the other.
OPTION 4: "The data for shelter B are a symmetric data set."
This is TRUE because the length of both whiskers are relatively equal, and also, the rectangular box is divided equally.
OPTION 5: "The interquartile range for shelter A is 8"
This is NOT TRUE.
IQR = Q3-Q1
IQR for shelter A is approximately = 28-17 = 11
Answer:
Average size of the lots = ⅓ acre
Step-by-step explanation:
The question incomplete without specifying what we are to determine.
Question:A builder is buying property where she can build new houses. The line plot shows the sizes for each house. 1/6 has 6 X's 1/3 has 3 X's and 1/2 has 6 X's. Organize the information in a line plot. What is the average size of the lots? _________ acre
Help anyone?
Solution:
We are asked to organize the information in a line plot. See attachment for the line plot.
Given: 1/6 has 6 X's 1/3 has 3 X's and 1/2 has 6 X'sIn no particular order, the sizes of the lots are:1/6, 1/6, 1/6, 1/6, 1/6, 1/6, 1/3, 1/3, 1/3, 1/2, 1/2, 1/2, 1/2, 1/2 and 1/2 acre.
Let's count the number of lot for each size given.
For 1/6: there are 6 X's on the line plot of 1/6 number of lot for 1/6
= the lot × number of times it occurs
= (1/6) × 6 = 6/6 = 1 acre
For 1/3: there are 3 X's on the line plot of 1/3 number of lot for 1/3 = the lot × number of times it occurs
= (1/3) × 3 = 3/3 = 1 acre
For 1/2: there are 6 X's on the line plot of 1/2 number of lot for 1/2
= the lot × number of times it occurs
= (1/2) × 6 = 6/2= 3 acres
To find average size of the lots, we would sum all lot for each given size then divide by the total number of lots given.Sum of all lot for each given size = 1+1+3
Sum of all lot for each given size = 5
The total number of lots given = 15
Average size of the lots = 5/15 = 1/3
Average size of the lots = ⅓ acre
