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otez555 [7]
3 years ago
12

Find y. (leave answer in simplest radical form) *

Mathematics
1 answer:
just olya [345]3 years ago
4 0

Answer:17.32

Step-by-step explanation:

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Simplify the rational Expression <br>​
qaws [65]

Answer:

\frac{x^2+2x}{x-3}

Step-by-step explanation:

We need to factor out numerator and denominator in order to simplify the rational expression by cancelling  common factors.

Numerator :  x^3 - 4 x = x (x^2 - 4) = x (x - 2) (x + 2)

Denominator (factoring by grouping):

x^2 - 5 x + 6 = x^2 - 3 x - 2 x + 6 = x (x - 3) - 2 (x - 3) = (x - 3) (x - 2)

Then we can cancel out the common factor (x - 2) in both numerator and denominator, leading to:

x (x + 2) / (x - 3) = (x^2 + 2)/ (x-3)

\frac{x^2+2x}{x-3}

4 0
3 years ago
I need a quick answer. I will appreciate your efforts
drek231 [11]

Answer:

10.5 cm

Step-by-step explanation:

12÷9= 1.3 (1dp)

14÷(12÷9)= 10.5cm

7 0
3 years ago
Read 2 more answers
Solve the equation <br> P = t+ r+ s for t
deff fn [24]

Answer:

t=p-r-s

Step-by-step explanation:

just bring r and s to the other side

6 0
3 years ago
How can you use a rate to compare costs of two boxes of cereal that are different sizes
MatroZZZ [7]
A rate shows how much larger or smaller one box is to the other box.
6 0
3 years ago
Suppose you have two​ populations: Population Along dashAll students at a state college ​(Nequals​21,000) and Population Blong d
Leno4ka [110]

Answer:

See the explantion below

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

X \sim N(\mu, \sigma)

We know that the margin of error for a confidence interval is given by:

Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

If we see the formula (1) at the same confidence level, for example 95% and with the same sample size the margin of error just depends of the deviation. If the population deviation for population A is higher than the population deviation for B then A will have more margin of error than B.

On the other case if the deviation for population A is lower than the deviation for population B, then we will have less margin of error for population A than population B.

And the other possible case if both population have the same deviation, then both have equal margin of error.  

6 0
4 years ago
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