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tia_tia [17]
2 years ago
11

What is 0.02349 written in standard form to 3 significant figures

Mathematics
1 answer:
zalisa [80]2 years ago
4 0

Solve from right to left

\\ \sf\Rrightarrow 0.02349

\\ \sf\Rrightarrow 0.0235\times 10^{-1}

\\ \sf\Rrightarrow 2.35\times 10^{-3}

Option C is correct

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Find the inverse of h(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B2x%2B6%7D%7B5%7D" id="TexFormula1" title="\frac{2x+6}{5}"
Dima020 [189]

Answer:

The inverse of h(x) is \frac{5x-6}{2}

Step-by-step explanation:

* Lets explain how to make the inverse of a function

- To find the inverse of a function we switch x and y and then solve

  for new y

- You can make it with these steps

# write g(x) = y

# switch x and y

# solve for y

# write y as g^{-1}(x)

* Lets solve the problem

∵ h(x)=\frac{2x+6}{5}

# Step 1

∴ y=\frac{2x+6}{5}

# Step 2

∴ x=\frac{2y+6}{5}

# Step 3

∵ x=\frac{2y+6}{5}

- Multiply each side by 5

∴ 5x = 2y + 6

- Subtract 6 from both sides

∴ 5x - 6 = 2y

- Divide both sides by 2

∴ y=\frac{5x-6}{2}

# Step 4

∴ h^{-1}(x)=\frac{5x-6}{2}

3 0
3 years ago
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Step-by-step explanation:

4 0
4 years ago
The diagnols of a rhombus are 21 and 16 centimeters long find the area of the rhombus
mr_godi [17]

Answer:

  168 cm²

Step-by-step explanation:

The area of a quadrilateral with diagonals that intersect at right angles is half the product of the lengths of the diagonals. A rhombus is one such quadrilateral, so the area of this one is ...

  A = 1/2(d1)(d2)

  A = (1/2)(21 cm)(16 cm) = 168 cm²

The area of the rhombus is 168 cm².

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3 years ago
1) lf 550m of wire is required to fence a circular
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Answer:

Step-by-step explanation:

4×2×πr=550

r=550/8π≈27.88 m

8 0
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The end of the rain gutter has the shape of a trapezoid with the measurements shown. Find the area of this end.
sladkih [1.3K]
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Area = 1/2 × (6+4) × 4 = 10×2 =20in ^2

AREA = 20 in squared

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5 0
3 years ago
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