1 gal + 2 qt + 3 pts
1 gal + 3 qt + 7 pts
1 gal + 3 qt + 3 pts
----------------------------add
3 gal + 8 qt + 13 pts
1 gal = 4 qts
1 gal = 8 pts
1 pt = 1/2 qt
13 pts = 6.5 qts
now we have 3 gal + (8 + 6.5) = 3 gal + 14.5 qts
12 qts = 3 gal
now we have : 6 gal + 2.5 qts or 6 gal + 2 qts + 1 pt <=== answer
Answer:
The answer is C
Step-by-step explanation:
Hope this helps.
This is a problem you need to solve using logs. When you use logs you can "pull" the exponents down in front of the log to get a new equation that looks like this: 2x^3 + x^2 log 81 = 6x - 3 log 27. Now divide both sides by log 81 and 6x - 3 simultaneously to get (2x^3 + x^2)/(6x - 3) = (log 27)/(log 81). If you do the log math on the right side you get .75. Now multiply both sides by 6x-3 to get 2x^3+x^2 = .75(6x-3). If you distribute that out on the left side you'll get 2x^3+x^2=4.5x-2.25. Now move everything over to the left side and set the whole thing equal to 0: 2x^3+x^2-4.5x+2.25=0. When you solve for x, you are in essence factoring, so do this by grouping: x^2(2x+1)-2.25(2x+1). Now finally factor out the 2x+1 to get (2x+1)(x^2-2.25). You're not done yet though cuz you need to solve each of those for x: 2x+1=0, and x= -1/2; x^2=2.25, and x=+/- 1.5. So all the values for x here are -1/2, 1.5, and -1.5
It’s an logistic management i don’t know what is the question doe
Answer:
The equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4) is x=-5
Option A is correct.
Step-by-step explanation:
We need to find equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4)
We need a line parallel to x=-2 or x+2=0 it should be of form x+k=0
We need to find k, by putting value of x=-5 as given in question the point(-5,4)
-5+k=0
k=5
So, the equation of line will be found by putting k=5:
x+k=0
x+5=0
x=-5
So, the equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4) is x=-5
Option A is correct.
