Answer:
A=10506.25 Sq.yards
Step-by-step explanation:
Width of the park=85 yds
Lenght of the park=120 yds
Now,
A=L*W
A=120*85
A=10200 square yards. This is the area of your given rectangle.
Now,
P=2(L+W)
P=2(120+85)
P=2(205)
P=410 this is the perimeter of your given rectangle.
Now,
a=410/4=102.5
Now,calculate the area of newly given distance of each side:
A=a^2
A=102.5^2
A=10506.25 Sq. Yards
This is the new area and is larger than the area of the given rectangle which was 10200 square yards.
It would be 9.54x10^6 because the nine is 6 spaces away from the decimal point if you get what i mean.
Answer: Both families were travelling at the same speed/rate of 1mile/0.65mins or 1mile/0.01hr.
Step-by-step explanation: Speed of Houck family's train = 552m/6hrs
speed of Robert family's train = 744m/8hrs.
Therefore considering Houck speed,
552miles = 6hours
1mile = (6 x 60)/552
= 360/552
= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr
For Robert
744miles = 8hours
1mile = ( 8 x 60 )/744
= (480/744)minutes
= 0.645
= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr
Conclusion: Both families were travelling at the same speed/rate.
To get that minutes in hour, just divide by 60 to get concert to hours.
x = total amount split between Adam and Tom.
since we know the total amount split between both in a 18 : 17 ratio is "x", let's divide "x" by (18 + 17) and distribute accordingly to get the amount of each.
![\stackrel{Adam~received}{18\cdot \cfrac{x}{18+17}}\qquad \qquad \stackrel{Tom~received}{17\cdot \cfrac{x}{18+17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since we know that Adam got "5" more}}{ \stackrel{Adam}{18\cdot \cfrac{x}{18+17}}~~ = ~~\stackrel{Tom}{17\cdot \cfrac{x}{18+17}~~ + ~~5} }\qquad \implies \qquad \cfrac{18x}{35}~~ + ~~\cfrac{17x}{35}+5](https://tex.z-dn.net/?f=%5Cstackrel%7BAdam~received%7D%7B18%5Ccdot%20%5Ccfrac%7Bx%7D%7B18%2B17%7D%7D%5Cqquad%20%5Cqquad%20%5Cstackrel%7BTom~received%7D%7B17%5Ccdot%20%5Ccfrac%7Bx%7D%7B18%2B17%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bsince%20we%20know%20that%20Adam%20got%20%225%22%20more%7D%7D%7B%20%5Cstackrel%7BAdam%7D%7B18%5Ccdot%20%5Ccfrac%7Bx%7D%7B18%2B17%7D%7D~~%20%3D%20~~%5Cstackrel%7BTom%7D%7B17%5Ccdot%20%5Ccfrac%7Bx%7D%7B18%2B17%7D~~%20%2B%20~~5%7D%20%7D%5Cqquad%20%5Cimplies%20%5Cqquad%20%5Ccfrac%7B18x%7D%7B35%7D~~%20%2B%20~~%5Ccfrac%7B17x%7D%7B35%7D%2B5)
![\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{35}}{35\left( \cfrac{18x}{35} \right)~~ = ~~35\left( \cfrac{17x}{35}+5 \right)}\implies 18x~~ = ~~17x+175\implies \boxed{x =175} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{Tom~received}{17\cdot \cfrac{x}{18+17}}\implies \cfrac{17(175)}{35}\implies \blacktriangleright 85 \blacktriangleleft](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B35%7D%7D%7B35%5Cleft%28%20%5Ccfrac%7B18x%7D%7B35%7D%20%5Cright%29~~%20%3D%20~~35%5Cleft%28%20%5Ccfrac%7B17x%7D%7B35%7D%2B5%20%5Cright%29%7D%5Cimplies%2018x~~%20%3D%20~~17x%2B175%5Cimplies%20%5Cboxed%7Bx%20%3D175%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7BTom~received%7D%7B17%5Ccdot%20%5Ccfrac%7Bx%7D%7B18%2B17%7D%7D%5Cimplies%20%5Ccfrac%7B17%28175%29%7D%7B35%7D%5Cimplies%20%5Cblacktriangleright%2085%20%5Cblacktriangleleft)
L.H.S is already equal, so just subtract 1st equation from second,
2y = 12
y = 6
Now, substitute it in 1st equation,
2(6) = 4x + 8
4x = 12 - 8
x = 4/4
x = 1
In short, Your Answer would be Option C) (1, 6)
Hope this helps!
