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3 years ago

Circumference and Area questions look at the picture

Mathematics

1 answer:

Helga [31]3 years ago

5 0

Note that the formula for the circumference of a circle is πd, while the formula for the area of a circle is πr².

π≈3.14

A. C=πd

Simply plug in the numbers into the formula.

Diameter=Radius*2

17*2=34

C=34(π)

B. (π)(5²)

Plug in the numbers into the formula. Remember that half of the diameter is the radius.

C. (π)(4.5)

There are two possible formulas that could be used to calculate the circumference of a circle: πd and 2πr.

The expression above is simply multiplying the circle's radius times pi. Therefore, it is not a method that could be used to find the circumference of a circle.

D. (π)(6.5²)

Remember that the formula for calculating the area of a circle is πr².

Half of the diameter is 6.5 (13.5/2=6.5). 6.5 cm. is the radius. Now just plug the numbers into the formula.

(π)(6.5²)

Therefore, the last answer choice is the correct answer.

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Can someone plz help me with this one problem plz I really need this to be correct!!!

daser333 [38]

Answer:

The answers would be 5.42 and 5.1.

Step-by-step explanation:

The diagram shows 5.39, so those answers would be more than the diagram shows.

3 0

3 years ago

HELP PLSS !!! Will mark as brainiest

Natasha_Volkova [10]

Answer:

$1709.92cm^3$

Step-by-step explanation:

$V=\pi r^2h=\pi *3^2*7=197.92cm^2$ (cylinder)

$V=whl=14*9*12=1512cm^3$ (rectangular prism)

$197.92+1512=1709.92cm^3$ (whole shape)

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3 years ago

Is the following statement true or false?

Kazeer [188]

Answer:

False

Step-by-step explanation:

Perpendicular angles create a 90°.

This is because two lines intersect to form a right angle,the lines are therefore perpendicular and creates a 90°.

Thank u.

7 0

3 years ago

What degree of rotation is represented on this matrix

Korvikt [17]

Answer:

Option B is correct

the degree of rotation is, $-90^{\circ}$

Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

$R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$

Given the matrix: $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

Now, equate the given matrix with standard matrix we have;

$\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$ = $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

On comparing we get;

$\cos \theta = 0$ and $-\sin \theta =1$

As,we know:

$\cos \theta = \cos(-\theta)$

$\sin(-\theta) = -\sin \theta$

$\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

and

$\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

Therefore, the degree of rotation is, $-90^{\circ}$

7 0

3 years ago

What is log3 ( x+5)=2?

Naddik [55]

(3) is the base of the new equation

(x + 5) is the answer of the new equation

(2) is the exponent on base (3)

;The new equation after simplifying is...,

; 3^2 = x + 5

; 9 = x + 5

; x = 9 - 5

;Hence...x = 4

4 0

3 years ago