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4 years ago

15

Find the circumference of the given circle 11 ft

1 answer:

nasty-shy [4]4 years ago

5 0

Answer:

69.12

Step-by-step explanation:

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How do the numerator and denominator of a fraction compare with the dividend and divisor of a division expression?

Julli [10]

The numerator is like the divided and the denominator is like the divident.

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3 years ago

What is 7x -2=26 I need help

miss Akunina [59]

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3 years ago

Read 2 more answers

[4H-16] A bottle of orange juice is being filled by machine. Amount dispensed by the machine is known to be approximately normal

Assoli18 [71]

Answer:1.5625

Step-by-step explanation:

Given

mean $\mu =10 ounces$

standard deviation $\sigma =m ounces$

For bottles to be filled over 12 ounces i.e. area right to the bell curve for z score

and area left side of the z score is 1-0.1=0.9

so value close to 0.9 in standard normal curve which is 0.8997

z score corresponding to 0.8997 is 1.28

also z score for 12 ounce

$z=\frac{x-\mu }{\sigma }$

$z=\frac{12-10}{m}$

$1.28=\frac{2}{m}$

$m=\frac{2}{1.28}$

$m=1.5625$

8 0

3 years ago

1. The position of a particle moving along a coordinate axis is given by: s(t) = t^2 - 5t + 1. a) Find the speed of the particle

zimovet [89]

Answer: $\left | 2t-5\right |,\ 2,\ 2t-5$

Step-by-step explanation:

Given

Position of the particle moving along the coordinate axis is given by

$s(t)=t^2-5t+1$

Speed of the particle is given by

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left | 2t-5\right |$

Acceleration of the particle is

$\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2$

velocity can be negative, but speed cannot

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=2t-5$

3 0

3 years ago

PLZ HELP! 20 POINTS!

agasfer [191]

Answer:

a) The error is that, the initial value is n=1 NOT n=3

b) The sum is $a_n=a_{n+1}+5=192$

c)The explicit formula is $a_n=5n+3$

The recursive formula is $a_n=a_{n+1}+5$ ,

Step-by-step explanation:

The given arithmetic series is 8 + 13 + ... + 43.

The first term is $a_1=8$ , the common difference is $d=13-8=5$

The nth term is given by:

$a_n=a_1+d(n-1)$

We substitute the values to get:

$a_n=8+5(n-1)\\a_n=8+5n-5\\\\a_n=3+5n$

To find how many terms are in the sequence we solve the equation:

$3+5n=43\\\implies 5n=43-3\\5n=40\\n=8$

The summation notation is $\sum_{n=1}^8(3+5n)$

The error the student made is in the initial value.

It should be n=1 NOT n=3

b) The sum of the arithmetic series is calculated using:

$S_n=\frac{n}{2}(a+l)$

We substitute o get:

$S_8=\frac{8}{2}(5+43)$

$S_8=4(48)$

$S_8=192$

c) The explicit formula we already calculated in a), which is $a_n=3+5n$

The recursive formula is given as:

$a_n=a_{n+1}+d$

We substitute d=5 to get:

$a_n=a_{n+1}+5$

6 0

3 years ago