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3 years ago

What does 2 + 2 equal

Mathematics

2 answers:

sergeinik [125]3 years ago

7 0

The sum to 2 plus 2 would equal 4

ANTONII [103]3 years ago

4 0

2+2=4. When adding the two digits together, you can either use a calculator or your fingers since the numbers are so low on the number chart.

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What is the average rate of change of the function f(x)= 2^x - 3 from x= 4 and x= 6?

WITCHER [35]

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7 0

3 years ago

A circle has a sector with area 24/5pi and central angle of 48°. What is the area of the circle? Either enter an exact answer in

ra1l [238]

Answer:

Area_circle = pi*(24/5)*(360/48)=36pi = 113.097

5 0

3 years ago

Solve for x. help me please

Marina86 [1]

Answer:

the answer is 20

Step-by-step explanation:

180+180=360

80+70=150

180-150=20

5 0

2 years ago

Read 2 more answers

HELP ME TVT I beg you (answer by yes or no)

aliya0001 [1]

Answer:

1:yes 2:no 3:no 4:yes

Step-by-step explanation:

3*2=6 for the numerators

4*5=20 for the denominators

you can simplify this to make it 3/10 ✔️

2*5-10 for the numerators

6*5=30 for the denominators

you can simplify this to make it 1/3 ❌

1*1=1 for the numerators

10*5 for the denominators

you can turn this into 1/50 ❌

1*3=3 for the numerators

2*5=10 for the denominators

you can turn this into 3/10 ✔️

hope this helps! have a nice day! :)

5 0

2 years ago

About 33% of people who get their feet examined are found to have an ingrown toenail. What is the probability of a podiatrist ex

enot [183]

Answer:

The correct answer is 0.94147

Step-by-step explanation:

Let A denote the event that the podiatrist finds the first person with an ingrown toenail.

And (1 - A) denote the event that the podiatrist does not find the ingrown toenail.

While examining seven people, the podiatrist can find the very first person to have an ingrown toenail. Similarly he can find the second patient to have the ingrown toenail. Going in this way the probability of the first person to have an ingrown toenail is given by:

= A + (1 - A) × A + (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A.

= $\frac{1}{3} + \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} .$

= $\frac{1}{3} + \frac{2}{3} \frac{1}{3} + (\frac{2}{3}) ^{2} \frac{1}{3} + (\frac{2}{3})^{3} \frac{1}{3} + (\frac{2}{3})^{4} \frac{1}{3} + (\frac{2}{3})^{5} \frac{1}{3} + (\frac{2}{3})^{6} \frac{1}{3}.$

= 0.94147

We can also solve the above expression by using the geometric progression formula as well where common ratio is given by $\dfrac{2}{3}$ .

8 0

3 years ago