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3 years ago

Write the log equation as an exponential equation. You do not need to solve for x.

Mathematics

1 answer:

aliya0001 [1]3 years ago

8 0

9514 1404 393

Answer:

x^2 -5x +14 = 10^(2x +4)

Step-by-step explanation:

The relationship is ...

log(a) = b ⇔ a = 10^b

Using this with a=x^2-5x+14 and b=2x+4, we have ...

x^2 -5x +14 = 10^(2x +4)

_____

<em>Additional comments</em>

In plain text, the exponent needs parentheses, because superscript formatting is not available to tell what is and isn't part of the exponent.

The base of "log" is assumed to be 10 in high school algebra. In the larger world, "log" is often used in place of "ln" to mean the logarithm to base 'e'.

The one solution is approximately x = −1.32505947996.

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