Answer:
12 possibilities
Step-by-step explanation:
In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.
The same thing occurs in the second urn, as all balls have different labels.
The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).
For the first urn, we have a combination of 4 choose 2:
C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities
For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.
In total we have 6 + 6 = 12 possibilities.
So, first turn your fractions into decimals. ⅞ = 0.875 which rounded is 0.88. 4/5 = 0.8. Next, put the decimals into the equation to replace the fractions. 0.88 + 4.2 - 0.8. Next solve the problem. So 0.88 + 4.2 = 5.08. Now your equation should look like this 5.08 - 0.8. Then subtract 0.8 from 5.08 which gives you 4.28. So 4.28 is your answer.
Answer:
1) a = 110
2) b = 65
3) c = 115 d= 65 e = 115
How I found the last one?
The whole thing equals 360.
d is equal to 65 so I added those together.
That equals 130. So i subtracted that from 360.
I got 230. Next, I divided that by 2 to get the final 2 angles.
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
• 1 + cot² x = csc²x and csc x = 
• sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x
Consider the left side
sin²Θ( 1 + cot²Θ )
= sin²Θ × csc²Θ
= sin²Θ × 1 / sin²Θ = 1 = right side ⇔ verified
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Consider the left side
cos²Θ - sin²Θ
= cos²Θ - (1 - cos²Θ)
= cos²Θ - 1 + cos²Θ
= 2cos²Θ - 1 = right side ⇒ verified
The formula is (degree)x(pi÷180)
36 x pi ÷ 180
0.63 rad