2x + 3y = 6.....multiply by 3
-3x + 5y = 10...multiply by 2
-----------------
6x + 9y = 18 (result of multiplying by 3)
-6x + 10y = 20 (result of multiplying by 2)
-----------------add
19y = 38
y = 38/19
y = 2
2x + 3y = 6
2x + 3(2) = 6
2x + 6 = 6
2x = 6 - 6
2x = 0
x = 0
solution is : (0,2)
sorry but the digits after 18 are unclear. are they singular or going together in 2s or is it one big number?
Answer:
30
Step-by-step explanation:
15% of 200 = 30
(2u² - 7) ÷ (u + 3)
2u² + 0u - 7 ÷ u + 3
2u - 6
u + 3 I 2u² + 0u - 7
- 2u² + 6u
0 - 6u - 7
+ - 6u - 18
0 + 11
Answer is: B. 2u - 6 R 11
To find the x value of the max of
f(x)=ax^2+bx+c
when a is negative (if a is positive, we find the minimum)
we do
-b/2a is the x value
to find the y value, we just sub that x value back into the function
so
R(x)=-0.2x^2+60x+0
-b/2a=-60/(2*0.2)=-60/-0.4=150
x value is 150
make 150 units
sub back to find revenue
R(150)=-0.2(150)^2+60(150)
R(150)=-0.2(22500)+9000
R(150)=-4500+9000
R(150)=4500
max revenue is achieved when 150 units are produced yeilding $4500 in revenue
