Evaluate 3z + 6 when z=4
2 answers:
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Answer:
The axis of symmetry is at
The graph has an x-intercept at
The graph has a vertex at
Step-by-step explanation:
we have
Statements
case 1) The graph has root at and
The statement is False
Because, the roots of the quadratic equation are the values of x when the value of y is equal to zero (x-intercepts)
Observing the graph, the roots are at and
case 2) The axis of symmetry is at
The statement is True
Observing the graph, the vertex is the point
The axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex
so
the equation of the axis of symmetry is
case 3) The graph has an x-intercept at
The statement is True
see procedure case 1)
case 4) The graph has an y-intercept at
The statement is False
Because, the y-intercept is the value of y when the value of x is equal to zero
Observing the graph, the y-intercept is the point
case 5) The graph has a relative minimum at
The statement is False
Because, is a vertical parabola open downward, therefore the vertex is a maximum
The point represent the vertex of the parabola, so is a maximum
case 6) The graph has a vertex at
The statement is True
see the procedure case 5)
see the attached figure to better understand the problem
Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. At time = 1.25 seconds, the gum is at a maximum height above the ground and 1 second later the gum is on the ground again.
a. If the diameter of the wheel is 68 cm, write an equation that models the height of the gum in centimeters above the ground at any time, t, in seconds.
b. What is the height of the gum when Lamaj gets to the end of the block at t = 15.6 seconds?
c. When are the first and second times the gum reaches a height of 12 cm?
Answer:
Step-by-step explanation:
a)
We are being told that:
Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. This keeps the wheel of his bike in Simple Harmonic Motion and the Trigonometric equation that models the height of the gum in centimeters above the ground at any time, t, in seconds. can be written as:
where;
y = is the height of the gum at a given time (t) seconds
34 = amplitude of the motion
the amplitude of the motion was obtained by finding the middle between the highest and lowest point on the cosine graph.
= the period of the graph
1.25 = maximum vertical height stretched by 1.25 m to the horizontal
b) From the equation derived above;
if we replace t with 1.56 seconds ; we can determine the height of the gum when Lamaj gets to the end of the block .
So;
Thus, the gum is at 58.01 cm from the ground at t = 15.6 seconds.
c)
When are the first and second times the gum reaches a height of 12 cm
This indicates the position of y; so y = 12 cm
From the same equation from (a); we have :
t = 2.72 seconds
Similarly, replacing cosine in the above equation with sine; we have:
t = 2.527 seconds
Hence, the gum will reach 12 cm first at 2.527 sec and second time at 2.72 sec.