Question

Can someone answer this pls??

Answer 1

Explanation

• Given the expressions and values.

$\frac{2ab + {a}^{2} {b}^{2} - a}{ab} \\ \begin{cases} a = - 1 \\ b = 1 \end{cases}$

• Substitute the value of a and b in the expression to evaluate.

$\frac{2( - 1)(1) + {( - 1)}^{2} {(1)}^{2} - ( - 1)}{( - 1)(1)}$

• Evaluate

$\frac{2( - 1) + 1(1) + 1}{ - 1} \\ \frac{ - 2 + 1 + 1}{ - 1} \\ \frac{ - 2 + 2}{ - 1} \\ \frac{0}{ - 1} \Longrightarrow 0$

Answer

$\large \boxed{0}$