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3 years ago

Can someone answer this pls??

Mathematics

1 answer:

babymother [125]3 years ago

3 0

<h3><u>Explanation</u></h3>

Given the expressions and values.

$\frac{2ab + {a}^{2} {b}^{2} - a}{ab} \\ \begin{cases} a = - 1 \\ b = 1 \end{cases}$

Substitute the value of a and b in the expression to evaluate.

$\frac{2( - 1)(1) + {( - 1)}^{2} {(1)}^{2} - ( - 1)}{( - 1)(1)}$

Evaluate

$\frac{2( - 1) + 1(1) + 1}{ - 1} \\ \frac{ - 2 + 1 + 1}{ - 1} \\ \frac{ - 2 + 2}{ - 1} \\ \frac{0}{ - 1} \Longrightarrow 0$

<h3><u>Answer</u></h3>

<u> $\large \boxed{0}$ </u>

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The graph is attached.

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(A.)test statistic for this test using Ha: p8くPN is Z = -2.164 (B.) p-value (3 decimal places) is 0.015. (C.) Based on this p-value, which of the following would you expect for a 95% is negative. (D.) the correct conclusion is The proportion of Boston drivers wearing seat was significantly lower than the proportion of new York drivers wearing seat belts.

A.)

According to given data find the test statistic for this test using Ha:

p1 = 0.581

p2 = 0.832

standard error = SE = 0.116

<h3>Test statistics :-</h3>

Z = $\frac{p1 - p2}{SE}$

Z = $\frac{0.581 - 0.832}{0.116}$ = -2.164

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B.)

According to given Determine the p-value (3 decimal places).

<h3>p - value</h3>

it is left tailed test.

p - value for left tailed test is,

p - value = P(Z < test statistics )

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C.)

Based on this p-value, which of the following would you expect for a 95%

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P -value is less than 0.05

so, reject null hypothesis at α = 0.05

That is $P_{B}$ < $P_{NY}$

so, based on P - value , All values in the 95% confidence interval

PB - PNY is negative.

D.)

According to given data What is the correct conclusion?

Reject null hypothesis at α = 0.05

so, $P_{B}$ < $P_{NY}$

Hence, The proportion of Boston drivers wearing seat was significantly lower than the proportion of new York drivers wearing seat belts.

know more about test statics visit this link

brainly.com/question/23332597

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