All categories

3 years ago

Can someone answer this pls??

Mathematics

1 answer:

babymother [125]3 years ago

3 0

<h3><u>Explanation</u></h3>

Given the expressions and values.

$\frac{2ab + {a}^{2} {b}^{2} - a}{ab} \\ \begin{cases} a = - 1 \\ b = 1 \end{cases}$

Substitute the value of a and b in the expression to evaluate.

$\frac{2( - 1)(1) + {( - 1)}^{2} {(1)}^{2} - ( - 1)}{( - 1)(1)}$

Evaluate

$\frac{2( - 1) + 1(1) + 1}{ - 1} \\ \frac{ - 2 + 1 + 1}{ - 1} \\ \frac{ - 2 + 2}{ - 1} \\ \frac{0}{ - 1} \Longrightarrow 0$

<h3><u>Answer</u></h3>

<u> $\large \boxed{0}$ </u>

You might be interested in

Find the values of x and y.

Ipatiy [6.2K]

Value of X and Y is 90 and 26 respectively.

3 0

3 years ago

C+2c+12=75 find the value of c

tamaranim1 [39]

Answer:

c+2c+12=75

c = 21

Steps:

c+2c+12=75

Simplify both sides of the equation.

c+2c+12=75

(c+2c)+(12)=75(Combine Like Terms)

3c+12=75

Subtract 12 from both sides.

3c+12−12=75−12

3c=63

Divide both sides by 3.

3 0

3 years ago

The coordinate plane below represents a city. Points A through F are schools in the city. graph of coordinate plane. Point A is

Firlakuza [10]

Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.

An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.

Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.

Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.

Part C:
Given that </span><span>Natalie can only attend a school in her designated zone and that Natalie's zone is defined by y < −2x + 2.

To identify the schools that Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.

For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true

For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true

For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false

For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true

For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false

For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
</span>

7 0

3 years ago

One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on

irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna = 237.08 ft

Step-by-step explanation:

The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°

distance from her position to the top of the building = 2475 ft

distance from her position to the top of the flag = 2615 ft

(a) How far away from the base of the building is the surveyor located?

using the SOHCAHTOA principle

cos 34° = c/2475

c = 0.8290375726 × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b = 0.5591929035 × 2475

b = 1384.0024361

b = 1384.00 ft

(c) What is the angle of elevation from the surveyor to the top of the antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ = 0.784665392

∅ = cos-1 0.784665392

∅ = 38.310258303

∅ = 38.31°

(d) How tall is the antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) = 0.6199159917 × 2615

(a + b) = 1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00 = 237.08031822 ft

Height of antenna = 237.08 ft

8 0

3 years ago

What is the least common multiple of 2, 6, 8, and 12?

Assoli18 [71]

24 because it’s the lowest multiple of 12 that’s also in 2,6 and 8

7 0

3 years ago

Read 2 more answers