The remainder (which is what Blake says is the remainder), can never be more than the number you are dividing by (the dividend), which in this problem is three.
Divide 136 by 3 and you will prove that answer is incorrect.
Answer:
0.62
Step-by-step explanation:
divide 56 by 90
Hope this helps :)
Answer:
- 13. (a) 120°, 120°, (b) 8.94 cm
- 14. (a) 17.9 cm, (b) 22.4 cm
Step-by-step explanation:
- <em>Refer to the attached sketch (not to scale)</em>
<h3>Question 13</h3>
(a) The center of the circle is also the circumcenter of the triangle PQR.
<u>Since ΔPQR is equilateral, all sides are equal, therefore opposite angles are also congruent:</u>
Sum of the three angles is 360° as cover the full circle.
<u>Each angle measure is:</u>
- ∠POQ = ∠QOR = ∠POR = 360°/3 = 120°
(b) Each side is 16 cm and the radius is 12 cm.
The distance of the midpoint M of PQ from the center O is perpendicular bisector of ΔPOQ.
<u>The segment MO is:</u>
- MO² = PO² - PM² = PO² - (PQ/2)²
- MO² = 12² - (16/2)² = 80
- MO = √80 = 8.94 cm (rounded)
<h3>Question 14</h3>
<u>ΔXYZ is isosceles with:</u>
- XY = XZ = 20 cm
- YZ = 18 cm
(a) The altitude of ΔXYZ is a perpendicular bisector of YZ. h = XM is the altitude
<u>Find h:</u>
- h² = XZ² - ZM² = XZ² - (ZY/2)²
- h² = 20² - (18/2)² = 319
- h = √319
- h = 17.9 cm (rounded)
(b) Note the ∠ZXM is half of the ∠ZOM as both the angles intercept half of the arc ZY and ∠ZOM is a central angle.
<u>Find ∠ZXM:</u>
- sin ∠ZXM = ZM/ZX = 9 / 20
- m∠ZXM = arcsin (9/20) = 26.7° (rounded)
<u>Find ∠ZOM:</u>
- m∠ZOM = 2*m∠ZXM = 2*26.7 = 53.4°
<u>Find the measure of the radius:</u>
- sin ∠ZOM = ZM/r
- sin 53.4° = 9/r
- r = 9 / sin 53.4°
- r = 11.2 cm (rounded)
<u>Find the measure of the diameter:</u>
- d = 2r = 2*11.2 cm = 22.4 cm
Answer:
km that is k×m means k is multiplied by m
Answer:
the other angles would be each 77°
and 2 angles are equal in an isosceles triangle
Step-by-step explanation:
hope it helps you