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goblinko [34]
3 years ago
5

Simplify the square root of 5 times the cube root of 5.

Mathematics
2 answers:
Allisa [31]3 years ago
4 0

Answer:

it's the third option!!!!!!!!!!!!

mihalych1998 [28]3 years ago
3 0

Answer:

Option 3 - five to the two thirds power

Step-by-step explanation:

Given : Expression 'the square root of 5 times the cube root of 5'.

To find : Simplify the expression ?

Solution :

Writing expression in numeric form,

The cube root of 5 means \sqrt[3]{5}

The square root of 5 times the cube root of 5 means \sqrt{5\sqrt[3]{5}}

Now, simplify the expression

\sqrt{5\sqrt[3]{5}}=\sqrt{5\times (5)^{\frac{1}{3}}}

\sqrt{5\sqrt[3]{5}}=\sqrt{(5)^{1+\frac{1}{3}}}

\sqrt{5\sqrt[3]{5}}=\sqrt{(5)^{\frac{4}{3}}}

\sqrt{5\sqrt[3]{5}}=((5)^{\frac{4}{3}})^{\frac{1}{2}}

\sqrt{5\sqrt[3]{5}}=(5)^{\frac{4}{3}\times \frac{1}{2}}

\sqrt{5\sqrt[3]{5}}=(5)^{\frac{2}{3}}

The expression is five to the two thirds power.

Therefore, Option 3 is correct.

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Consider the graph of the function f(x) = 25
trasher [3.6K]

Considering it's horizontal asymptote, the statement describes a key feature of function g(x) = 2f(x) is given by:

Horizontal asymptote at y = 0.

<h3>What are the horizontal asymptotes of a function?</h3>

They are the limits of the function as x goes to negative and positive infinity, as long as these values are not infinity.

Researching this problem on the internet, the functions are given as follows:

  • f(x) = 2^x.
  • g(x) = 2f(x) = 2(2)^x

The limits are given as follows:

\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 2(2)^x = \frac{2}{2^{\infty}} = 0

\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 2(2)^x = 2(2)^{\infty} = \infty

Hence, the correct statement is:

Horizontal asymptote at y = 0.

More can be learned about horizontal asymptotes at brainly.com/question/16948935

#SPJ1

3 0
2 years ago
HELP WILL GIVE 15 POINTS <br>what is the range of this function and pls explain​
Nataly [62]

Answer:

f(x)\geq -2

Step-by-step explanation:

Range corresponds to the values of y on the y-axis. If we see the graph the minimum value of the y-coordinate is -2 and then it tends to increase from it. We do not know till where the y values will increase in the figure it shows 6 but it's still actually increasing we keep on tracing the graph but the minimum value will always remain the same which is -2 . So we can say that the range of the function is

f(x)\geq -2\\

Where f(x) is the function and since the values of y on the y-axis increase from -2 we can say that the function has the range of values greater than or equal to -2

4 0
3 years ago
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