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Vikentia [17]
3 years ago
11

I would appreciate if someone could help me with this problem and answer it I will give you a brainlist :)

Mathematics
2 answers:
aev [14]3 years ago
8 0
To me from the picture, all sides look the same. so I’m guessing it’s probably 11
exis [7]3 years ago
6 0

Answer:

theres multiple answers but the answer your looking for is 11

Step-by-step explanation:

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Rewrite this standard form quadratic equation into vertex form by completing the square. Upload your work here to show your thin
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Solution :

Given the equation :

$y = x^2 - 6x+3 $

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$n = \left(\frac{b}{2}\right)^2$

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n = 9

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$y=1(x^2 - 6x +9)-9+3$

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Therefore the vertex form of $y = x^2 - 6x+3 $  is  $y=1(x-3)^2- 6$.

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Marta_Voda [28]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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