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2 years ago

Please help write a system of equations to represent the scenario

Mathematics

1 answer:

s344n2d4d5 [400]2 years ago

4 0

Equations:
x + y = 37
5x + 3y = 161

25 adult tickets
12 student tickets

—————-

Adult tickets are x
Student tickets are y
Equations are for number of tickets sold and price of tickets sold/money earned

x + y = 37
5x + 3y = 161

x = 37 - y

5(37 - y) + 3y = 161
185 - 5y + 3y = 161
- 2y = -24
y = 12

x = 37 - y
x = 37 - 12 = 25

Please let me know if you have questions about this answer

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Simplify 8-(-5) - 4(-7). О-63 оо ООО

Sergeeva-Olga [200]

8- (-5) - 4 (-7) = 41

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3 years ago

Calculate annually compounded interest

Hunter-Best [27]

Answer:

$2,851.80

Step-by-step explanation:

Lets use the compound interest formula to solve:

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, change 1.1% into a decimal:

1.1% -> $\frac{1.1}{100}$ -> 0.011

Next, plug the values into the equation:

$A=2,700(1+\frac{0.011}{1})^{1(5)}$

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3 years ago

Solve.

Nikitich [7]

The answer is C: $10\text{ }^1/_2$ . Here are the details:

$\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
16\text{ }^5/_6$

$\text{Equation:}\\
16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Start with the integers.}\\
16+3=19\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{...then with the fractions, but rewrite them first to make it easier.}\\
^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
20\text{ }^2/_3$

$\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add the integer and fraction together.}\\
25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6$

$26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6$

5 0

3 years ago

2+2 pls help btw 4 .....

Vsevolod [243]

Answer:

is it 22.

Step-by-step explanation:

is it?

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3 years ago

Read 2 more answers

Ronnie, Mack, Kim, and Ada together stacked a total of 40 pizzas in a pan. Ronnie stacked 0.25 of the pizzas, Mack stacked 9 of

natta225 [31]

Hello!

Here's how much each person stacked:

Ronnie -- 0.25 of the 40 pizzas.

Mack -- 9/40

Kim -- 35% of the 40 pizzas.

Ada -- rest of the pizzas.

Now, the questions asks for who stacked the most pizzas.

First, find our how many pizzas they stacked out of 40.

40 × 0.25 = 10

40 × 35% = 14

10 + 9 + 14 = 33

40 - 33 = 7

This means that Ronnie stacked 10 pizzas, Mack stacked 9 pizzas, Kim stacked 14 pizzas, and Ada stacked 7 pizzas.

ANSWER:

Kim stacked the most pizzas since she stacked 14 of them.

7 0

3 years ago

Read 2 more answers