A volleyball league organizer collected $2,040 for both divisions of volleyball teams. The Blue division costs $160 per team and the Red division cost $180 per team. How many teams will play in each division.
<h3><u>Answer:</u></h3>
6 teams will play in each division
<h3><u>
Solution:</u></h3>
Given that volleyball league organizer collected $2,040 for both divisions of volleyball teams
The blue division costs $160 per team
The Red division cost $180 per team.
Let the number of blue teams be "b"
Let the number of red teams be "r"
Total cost = number of blue teams x cost of blue division per team + number of red teams x cost of red division per team
Total cost = 160b + 180r
2040 = 160b + 180r
Assuming both divisions have the same number of teams, we substitute b = r = x
2040 = 160x + 180x
2040 = 340x
x = 6
So 6 teams will play in each division
Answer:
-10
Step-by-step explanation:
minus 5 in each number
No solution, the answer is no solution
Answer:
a) It can be used because np and n(1-p) are both greater than 5.
Step-by-step explanation:
Binomial distribution and approximation to the normal:
The binomial distribution has two parameters:
n, which is the number of trials.
p, which is the probability of a success on a single trial.
If np and n(1-p) are both greater than 5, the normal approximation to the binomial can appropriately be used.
In this question:
So, lets verify the conditions:
np = 201*0.45 = 90.45 > 5
n(1-p) = 201*(1-0.45) = 201*0.55 = 110.55 > 5
Since both np and n(1-p) are greater than 5, the approximation can be used.
Answer: 0.6 in 10 % ; 0.4 in 15 %
Step-by-step explanation:
1. (x*10%) + (y*15%)/ x+y=12%
2. x+y = 1 x= 1-y
(0.1x + 0.15y/ x+y= 12/100) * 100
(10x + 15y/x+y = 12)*(x+y)
10x+15y= 12x + 12y
-2x=-3y
2x = 3y 2(1 - y)= 3y
2-2y=3y 2= 5y
y= 0.4
x= 0.6
