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2 years ago

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If f(x)= x+4/x, g(x) = x-2, and h(x)= 4x-1, what is (fohog)

1 answer:

MrRa [10]2 years ago

5 0

The answer is d (fohog)= 4x-5/4x-9

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10. During the hockey season, Elena

Debora [2.8K]

Answer:

Step-by-step explanation:

If I remember expanded form is putting all number in terms of being times 10 to a power. starting with the ones place it's x10^0 which of course is just 1, so you don't need to include the x10 at all.

now, moving one either way that 0 either get 1 added to it or subtracted. So in the 10s place it becomes x10^1 and the tenths place becomes x10^-1. Similarly the hundreds place and hundreths place will have x10^2 and x10^-2 respectively. So keep this pattern going to find each place of the number. Can you list out what places are displayed in 5.625?

I will get you started, but let me know if you don't quite get it.

5 + 6*10^-1 + ...

Can you figure out the rest?

7 0

2 years ago

What quadrilateral has exactly one pair of parallel sided?

8_murik_8 [283]

It should be a trapezoid

6 0

2 years ago

Read 2 more answers

Some money is shared between erin, faye and sachin in the ratio 5:2:7. Faye gets £90 less than sachin. How much money did Erin g

VARVARA [1.3K]

Answer:

Erin gets £90

Step-by-step explanation:

Ratio = 5 : 2 : 7

Money with Erin = 5x

Money with Faye = 2x

Money with Sachin = 7x

Faye gets £90 less than Sachin

7x - 2x = 90

5x = 90

x = 90/5

x = 18

Money with Erin = 5*18 = 90

7 0

2 years ago

faltersainse [42]

Anything less than 90, i hope this helps

7 0

2 years ago

The federal government would like to test the hypothesis that the average age of men filing for Social Security is higher than t

mixas84 [53]

Answer:

The 90% confidence interval is $-0.3433< \mu_1 - \mu_2 < 2.1433$

Step-by-step explanation:

From the question we are told that

The sample mean for men is $\= x_1 = 64.5 \ years$

The sample mean for women is $\= x_2 = 63.6 \ years$

The sample size for men is $n_1 = 35$

The sample size for women is $n_2 = 39$

The standard deviation for men is $s_1 = 3.0$

The standard deviation for women is $s_2 = 3.5$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the standard error is mathematically represented as

$SE = \sqrt{\frac{s_1^2 }{n_1} + \frac{s_2^2}{n_2} }$

=> $SE = \sqrt{\frac{3^2 }{35} + \frac{3.5^2}{39} }$

=> $SE = 0.7558$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * SE$

=> $E = 1.645 * 0.7558$

=> $E = 1.2433$

Generally 90% confidence interval is mathematically represented as

$(\= x_1 - \= x_2) -E < \mu_1 - \mu_2 < (\= x_1 - \= x_2) -E$

=> $(64.5 - 63.6) -1.2433< \mu_1 - \mu_2$

=> $-0.3433< \mu_1 - \mu_2 < 2.1433$

7 0

2 years ago