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Colt1911 [192]
3 years ago
7

Which of the tables is a function? PLEASE HELP 15 POINTS or Brainlist answer!!!

Mathematics
1 answer:
Drupady [299]3 years ago
3 0

Answer:

I say C is your best answer because it might be a typo

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What is the following quotient? Sqrt 96/ Sqrt 8
Jobisdone [24]

Radicals cannot exist as a denominator, so you would multiply both Sqrt96 and Sqrt8 by the Sqrt8, giving you Sqrt768 over 8 (since a sqrt times itself is the base number, in this case 8) then you would simplify Sqrt768 into 16 x Sqrt3, leaving you with 16xSqrt3 over 8. simplify into 2Sqrt3 by dividing.

3 0
3 years ago
Read 2 more answers
Can someone answer this please and thank you
musickatia [10]

Answer:

See below.

Step-by-step explanation:

x+3/9=5/9

  -3/9  -3/9

x=2/9

--------------

11+x=50

-11     -11

x=39

-------------

2/9+x=8/9

-2/9     -2/9

x=6/9 or 2/3

-hope it helps

7 0
2 years ago
Mitch is buying candy bars for his friends. He wants to give 2 bars to each friend, and he wants to have 10 spare bars. He can a
gregori [183]

Answer:

A. 2f + 10 = 28

Step-by-step explanation:

28 candy bars.

He wants 10.

28 - 10.

18 candy bars.

He gives each friend 2.

18 divided by 2.

9.

He can treat 9 friends.

Step 1: Subtract 10 from both sides.

2f+10=28

which would take away the 10 and subtract 10 from 28. (That would be Jack's bars.)

2f = 28.

Step 2: Divide by 2 on both sides.

2f = 28

which would cancel out the 2f. And Whatever is done to the left is done to the right, meaning you would divide 28 by 2 aswell. (Dividing up the candy bars among his friends).

f = 9

6 0
3 years ago
Maximize the objective function P = 3x + 5y for the given constraints
Nikitich [7]
The answer is 19 please like and 5 star
7 0
2 years ago
7x^2=9+x what are the values of x<br><br>Will give medal and points
DENIUS [597]
7x² = 9 + x   Subtract x from both sides
7x² - x = 9    Subtract 9 from both sides
7x² - x - 9 = 0   Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x = \frac{-b \pm  \sqrt{b^2 - 4ac} }{2a}   Plug in the a, b, and c values
x = \frac{- (-1) \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Cancel out the double negative
x = \frac{1 \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Square -1
x = \frac{1 \pm  \sqrt{1 - 4(7)(-9)} }{2(7)}   Multiply 7 and -9
x = \frac{1 \pm  \sqrt{1 - 4(-63} }{2(7)}   Multiply -4 and -63
x = \frac{1 \pm  \sqrt{1 + 252} }{2(7)}   Multiply 2 and 7
x = \frac{1 \pm  \sqrt{1 + 252} }{14}   Add 1 and 252
x = \frac{1 \pm  \sqrt{253} }{14}   Split up the \pm
x = \left \{ {{ \frac{1 +  \sqrt{253} }{14} } \atop { \frac{1 -  \sqrt{253} }{14} }} \right.
The approximate square root of 253 is <span>15.905973.
</span>x ≈ \left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right   Add and subtract
x ≈ \left \{ {{ \frac{16.905973}{14} } \atop { \frac{14.905973}{14} }} \right.   Divide
x ≈ \left \{ {{1.2075} \atop {1.0647}} \right.   Round to the nearest hundredth
x ≈ \left \{ {{1.21} \atop {1.06}} \right.

<span>
</span>
7 0
3 years ago
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