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erik [133]
3 years ago
13

Write a polynomial of least degree with rational coefficients and with the root -19-5 square root 2.

Mathematics
1 answer:
iogann1982 [59]3 years ago
5 0

Answer:

y = x² + 38x + 311

Step-by-step explanation:

If a polynomial has rational coefficients and irrational roots, then the roots must be conjugate pairs.

y = (x − (-19-5√2)) (x − (-19+5√2))

y = (x + 19+5√2) (x + 19−5√2)

Use FOIL to distribute:

y = x² + x (19−5√2) + x (19+5√2) + (19+5√2)(19−5√2)

y = x² + 19x − 5√2 x + 19x + 5√2 x + (19+5√2)(19−5√2)

y = x² + 38x + (19+5√2)(19−5√2)

Use FOIL to distribute the last term:

y = x² + 38x + 19² − 95√2 + 95√2 − 50

y = x² + 38x + 361 − 50

y = x² + 38x + 311

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X2 + y2 + 42x + 38y − 47 = 0. The equation of this circle in standard form is
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The Standard form of the equation of circle is (x+21)² + (y+19)² = 849

<h3>What is Standard form of circle?</h3>

To transform general form to a standard form, you can use completing the square method or you can convert this equation

x² + y² + Dx + Ey + F = 0 to x² + y² + (-2h)x + (-2k)y + (h²+k²-r²) = 0

Here, Given: x² + y² + 42x + 38y − 47 = 0

Required: Find the values of h, k, and r using this formula

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Thus, the Standard form of the equation of circle is (x+21)² + (y+19)² = 849

Learn more about Circle from:

brainly.com/question/11833983

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