Given:
The slope of the line is m=0.
The line passes through the point P(-9,-3).
To find:
The equation of the line in standard form.
Solution:
Standard form of a line is:
The slope intercept form of the line is
Where, m is the slope and 
is the point on the line.
It is given that the slope of the line is 3 and it passes through the point (-9,-3), so the equation of the line is
Therefore, the standard form of the given line is .
Nope anyway marry Christmas
Answer:
y=-3x-14
Step-by-step explanation:
y=mx +c
m= 1/3
perp m= -3
goes through point (6,-4)
sub numbers
A=lw. Is the answer. Hope it helps
For cos(2x) * (2cos(x) + 1) = 0, use the double angle identity for cos(2x), which is cos^2 x - sin^2 x = cos^2 x - (1-cos^2) = 2cos^2 x - 1.
So we have (2cos^2 x - 1)(2cos x + 1) = 0. So 2cos^2 x -1 = 0 or x = 0 and 2pi.
For 2sec^2 x + tan^2 x - 3 = 0, use the identity sec^2 x = tan^2 x + 1, so we have
2(tan^2 x + 1) + tan^2 x - 3 = 0 or
<span>2tan^2 x + tan^2 x - 1 = 0 or
</span>3 tan^2 x = 1.
So x = pi/2, pi/2 + pi = 3pi/2.
