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Oxana [17]
3 years ago
6

Simplify. 9 + 8 + 3x 17 + 3 x 9 + 11 x 20 + x 20 x

Mathematics
2 answers:
omeli [17]3 years ago
6 0

Answer:

17+3x

that is the answer

malfutka [58]3 years ago
3 0

Answer:

17 + 3x

Step-by-step explanation:

9 + 8 + 3x

=17 + 3x

because the 3 contain a valuable x that why it is add to the 17

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Can someone help please!! i will give brainliest
olga_2 [115]

Answer:

1. $427.50

2. 50 hours

Step-by-step explanation:

1. First, find your salary at minimum hours, which is $360. Then, take your second equation, plug in 45, and solve using PEMDAS. This will give you $427.50

2. To solve this, you'll need to set it up like so:

495 = 13.5 (x - 40) + 360

Your next step will be to distribute the number outside the parentheses. This will give you:

495 = 13.5x - 540 + 360

Simplify, like so:

495 = 13.5x - 180

Solve.

495 = 13.5x - 180

+180             +180

This will give you:

675 = 13.5x

Divide each side.

675 = 13.5x

------    -------

13.5     13.5

  50 = x

7 0
3 years ago
Although the actual amount varies by season and time of day the average volume of water that falls over the falls each second is
bulgar [2K]
262.8*10 to the 7th power
3 0
3 years ago
Evaluate the expression.<br> 4.2°
Mariana [72]

Answer:

4.2°

Step-by-step explanation:

The result can be shown in <u>m</u><u>u</u><u>l</u><u>t</u><u>i</u><u>p</u><u>l</u><u>e</u> forms.

Exact Form: 4.2°

Decimal Form: 4.2

I hope this helps!

4 0
2 years ago
Write the equation of the given line in slope-intercept form.​
gizmo_the_mogwai [7]

Answer:

y = 2x - 1

Step-by-step explanation:

Slope intercept form: y=mx+b

point a: (1, 1)

point b: (2, 3)

1. Find the slope of the equation

Equation for slope(mx): (y2- y1)/ (x2-x1)

(3-1)/(2-1)= 2

slope: 2

2. Pick any of the two point to find the "b" and plug in the coordinates of the point to find the y-intercept of the equation.

point a: y=1, x=1

y=mx+b

1=2(1) + b

b= -1

3. Plug the answers you found above into the slope-intercept form

Overall equation:

y=2x - 1

7 0
3 years ago
Explain why the quadratic relation y=2x^2+3x+5 would have no zeros
alex41 [277]

Complete the square to rewrite the quadratic:

2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5

... = 2 (<em>x</em>² + 3/2 <em>x</em> + 9/16 - 9/16) + 5

... = 2 (<em>x</em>² + 3/2 <em>x</em> + (3/4)²) + 5 - 9/8

... = 2 (<em>x</em> + 3/4)² + 31/8

Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.

5 0
3 years ago
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