i dont understand
Answer:
Step-by-step explanation:
ΔADC is a right angle triangle, we will use the Pythagorus Theorem to find the length CD.
Formula of the Pythagorus Theorem :
⇒ a² + b² = c²
⇒ AD² + CD² = AC²
The value of AD is 54 and the value of AC is 90:
54² + CD² = 90²
Solve for CD:
54² + CD² = 90²
CD² = 90² - 54²
CD² = 5184
CD = √5184
CD = 72
ΔADC is also a right angle triangle, we will use the Pythagorus Theorem to find the length BD.
Formula of the Pythagorus Theorem :
⇒ a² + b² = c²
⇒ BD² + CD² = BC²
The value of CD is 72 and the value of BC is 97:
BD² + 72² = 97²
Solve for BD:
BD² = 97² - 72²
BD² = 4225
BD = √4225
BD = 65
Answer: The length of BD is 65 units.
Answer:
57
Step-by-step explanation:
use a calculator lol
Angle B = Angle D and the sum of these two is 70. X must be 180-60 = 110 degrees.
The number of students would not change between before the test and after the test. 3+8 and 4+7 both = 11 so finding out how many students would equal one ratio can then be used to find how many equal 3 and 8.
If 92 students are equal to 4 in the ratio, then 1 in the ratio is worth 23 students. This is important as then when you times 23 by 7 you find out how many students there are in the regular maths class, 161 students. Plussing these two together gives you a total of 253 students.
Using this 253 you can divide it by 11 to find out how much 1 number would be in the ratio, it equals 23. Using this you can then times 23 by both 3 and 8 to find the original class sizes, 3x23 = 69, and 23x8 = 184.
Making the origional class size of the advaced class 69 studnets, and the regular maths class size 184.