Answer:
10 i think
Step-by-step explanation:
theres 10 x's
<h3>
Answer: (x+1)^3*(x-2)</h3>
Explanation:
It's probably not obvious, but the squiggly portion through the x intercept x = -1 is a triple root. This is because this portion resembles a cubic graph. If instead it was a more straightish line through this root, then we'd have a single root.
So because x = -1 is a triple root, this means the factor (x+1) has the exponent 3. We have the factor (x+1)^3
The other factor is (x-2) from x = 2 being the other root.
All together we have (x+1)^3*(x-2) as the complete factorization. The leading coefficient is 1 to have this graph open upward. Or put another way, since the end behavior is going to positive infinity for both endpoints, the leading coefficient must be positive.
6.02 in long. First you need to find 6/14 then you multiply that answer by 14
mixed number: 4 7/8 simplest form: (THERE IS NONE)
Answer:
1. |y| sqrt(10)
2. |x| sqrt(x)
3. a^2 sqrt(a)
4. 4 |y|^3 sqrt(3)
5. 1/4 *|x| sqrt(3x)
Step-by-step explanation:
1. sqrt(10y^2)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(y^2) sqrt(10)
|y| sqrt(10)
We take the absolute value of y because -y*-y = y^2 and the principle square root is y
2. sqrt(x^3)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(x^2) sqrt(x)
|x| sqrt(x)
3. sqrt(a^5)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(a^4) sqrt(a)
a^2 sqrt(a)
4. sqrt(16 y^7)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(16) sqrt(y^6)sqrt(y)
4 |y|^3 sqrt(3)
5. sqrt(3/16x^3)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(1/16) sqrt(x^2)sqrt(3x)
1/4 *|x| sqrt(3x)