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2 years ago

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Gavin and Ethan are training for a race. Last week,gavin ran 7 kilometers and Ethan ran twice as far as gavin what is the total

distance that gavin and Ethan ran last week express your answer in meters.

1 answer:

Irina18 [472]2 years ago

6 0

Answer:

14 km

Step-by-step explanation:

7x2

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What is the following product?

-Dominant- [34]

Answer:

98 - 40√6

Step-by-step explanation:

We have to simplify the following product :

$(5\sqrt{2} - 4\sqrt{3})(5\sqrt{2} - 4\sqrt{3})$ .

Now, $(5\sqrt{2} - 4\sqrt{3})(5\sqrt{2} - 4\sqrt{3})$

= $(5\sqrt{2} - 4\sqrt{3})^{2}$

= $(5\sqrt{2})^{2} - 2 (5\sqrt{2}) (4\sqrt{3}) + (4\sqrt{3} )^{2}$

{Since we know the identity (a - b)² = a² - 2ab + b² }

= 50 - 40√6 + 48

= 98 - 40√6 (Answer)

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3 years ago

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2/3 times what equals 24?

Vikki [24]

Answer:

2/3 x = 24

1/3 x = 12

x = 36

36

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3 years ago

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3x^2+2x+27 find g(p+4)

Alborosie

G(p+4)=3(p+4)^2+2(p+4)+27
=3p^2+24p+48+2p+8+27
=3p^2+26p+83

6 0

2 years ago

plz help doing test rn i need it

Roman55 [17]

Answer:

$|answer| \\ 1)0=0 \\ 2)0=28$

3)The example equation becomes "x + 10 - 15x = 20," which is then "-14 x + 10 = 20." Subtract 10 from each side, divide by 14 and you have end up with x = -10/14, which simplifies to x = -5/7. Plug in the x value in to the first equation to find out the y value. y = 2 - 3(-5/7) becomes 2 + 15/7, which is 29/7.

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2 years ago

Using the method of completing the square, put each circle into the form

tatiyna

Answer:

Standard form: $(x-\frac{1}{2})^2 + (y-0)^2 = 15$

Center: $(\frac{1}{2}, 0)$

Radius: $r =\sqrt{15}$

Step-by-step explanation:

The equation of a circle in the standard form is

$(x-h)^{2} + (y-k)^{2} = r^{2}$

Where the point (h, k) is the center of the circle

To transform this equation $4x^{2} -4x + 4y^{2} - 59 = 0$ this equation in the standard form we use the method of square.

First, we group similar variables

$(4x^{2} -4x) + (4y^{2}) - 59 = 0$

Divide both sides of equality by 4

$(x^{2} -x) + (y^{2}) - 14.75 = 0$

Now we complete square for variable x.

Take the coefficient "b" that accompanies the variable x and divide by 2. Then, elevate the result to the square:

$b =-1\\\\\frac{b}{2}= \frac{-1}{2}= -\frac{1}{2}\\\\(\frac{b}{2})^2= (-\frac{1}{2})^2 = \frac{1}{4}$

Now add $(\frac{b}{2})^2$ on both sides of the equality

$(x^{2} -x +\frac{1}{4}) + (y^{2}) - 14.75 = (\frac{1}{4})$

Factor the expression and simplify the independent terms

$(x-\frac{1}{2})^2 + (y^{2}) = 15$

$(x-\frac{1}{2})^2 + (y-0)^2 = 15$

Then

$h =\frac{1}{2}\\\\k=0$

and the center is $(\frac{1}{2}, 0)$

radius $r =\sqrt{15}$

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2 years ago