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Mumz [18]
3 years ago
11

Plz help befoe 11:20 i need help

Mathematics
1 answer:
Burka [1]3 years ago
8 0

Answer: During the second hour it could travel either 4,5,6,7,8,9 hours


Step-by-step explanation:


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Pls Help i dont understand ittttttttttt
agasfer [191]

The given scale for the map means that a distance of 1 cm between two locations on the map corresponds to a real distance between them of 600,000 cm = 6 km.

So, if the distance between two places in reality is 87 km, on the map this would be represented by a distance of 14.5 cm, since

87 = 84 + 3

87 = 6 • 14 + 6 • (1/2)

87 = 6 • (14 + 1/2)

3 0
2 years ago
How do I solve this problem 3y-6+7y-4y
VashaNatasha [74]
Let's simplify step-by-step.
3y-6+7y-4y
=3y+ -6+7y+ -4
Combine Like Terms.
=3y+ -6 +7y+ -4y
=6y+ -6
Answer:
6y-6
6 0
3 years ago
Lim<br> x-&gt;infinity (1+1/n)
FrozenT [24]

Answer:

^{ \lim}_{n \to \infty} (1+\frac{1}{n})=1

Step-by-step explanation:

We want to evaluate the following limit.


^{ \lim}_{n \to \infty} (1+\frac{1}{n})


We need to recall that, limit of a sum is the sum of the limit.


So we need to find each individual limit and add them up.

^{ \lim}_{n \to \infty} (1+\frac{1}{n})=^{ \lim}_{n \to \infty} (1) +^{ \lim}_{n \to \infty} \frac{1}{n}


Recall that, as n\rightarrow \infty,\frac{1}{n} \rightarrow 0 and the limit of a constant, gives the same constant value.



This implies that,


^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1 +0


This gives us,

^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1


The correct answer is D



5 0
3 years ago
T5 ( volume of cylinder )
yan [13]

Answer:

Step-by-step explanation:

V=\pi r^2h=\pi *20^2*8 ≈ 10053.1in^3

4 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST, THANKS, AND 5 STARS!<br> PLEASE HELP ME!
Bogdan [553]

Answer:

-4 and 4

Step-by-step explanation:

<u>Method 1</u>

Apply Difference of Two Squares Formula: a^2-b^2=(a+b)(a-b)

Given  x^2-16=0

Rewrite 16 as 4²

Therefore, a^2=x^2 and b^2=4^2

\implies a = \sqrt{x^2}=x

\implies b=\sqrt{4^2} =4

\implies x^2-16^2=(x+4)(x-4)

\implies (x+4)(x-4)=0

\implies (x+4)=0 \implies x=-4

\implies (x-4)=0 \implies x=4

<u>Method 2</u>

Given equation:

x^2-16=0

Add 16 to both sides:

\implies x^2-16+16=0 + 16

\implies x^2=16

Square root both sides:

\implies \sqrt{x^2}=\sqrt{16}

\implies x=\pm4

Therefore, x = -4, x = 4

6 0
2 years ago
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