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Inga [223]
2 years ago
14

2

Mathematics
1 answer:
almond37 [142]2 years ago
3 0

Answer:

I believe your answer would be C

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Find xy if x + y=3, x^2 + y^2 = 5
Vesna [10]

Answer:

mark me

Step-by-step explanation:

x+y=3

x=3-y

putting the value of x

in this

x²+y²=5

(3-y) ²+y²=5

9-6y+y²+y²=5

2y²-6y+9-5=0

2y²-6y+4=0

2y²-4y-2y+4=0

2y(y-2)-2(y-2)=0

(2y-2) (y-2) =0

2y-2=0 or y-2=0

y=1 or y=2

so x=2 or 1

so x×y=2×1 or 1×2=2

I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST

8 0
3 years ago
Simplify: –3(y 2)2 – 5 6y What is the simplified product in standard form? y2 y.
s344n2d4d5 [400]

The simplified product in standard form is ..

-3y^2 + -6y + -17

Edge 2022!

6 0
2 years ago
Is 12/20 greater than 1
Lapatulllka [165]

no, this is false. 1 is greater than 12/20.

6 0
2 years ago
Read 2 more answers
At the start of a mission, international spy James withdrew $5,000 in Cairo. In Istanbul, he withdrew half of the remaining mone
lord [1]

Answer:

Initial Amount at the start of the mission=\$20000

Step-by-step explanation:

Let initial amount=x

In Cario James withdrew \$5000.

Remaining Amount=x-5000

In Instanbul he with drew half of the remaining amount so half of the remaining amount will be left.

\frac{1}{2}\times(x-5000)=7500\\\\x-5000=15000\\\\x=20000

8 0
3 years ago
You place the spring vertically with one end on the floor. You then drop a book of mass 1.50 kg onto it from a height of 0.900 m
Alex777 [14]

Answer:

The value of the maximum distance the spring will be compressed  

x = 0.143 m= 14.3 cm

Step-by-step explanation:

Given data

Mass m = 1.5 kg

h = 0.9 m

k = 1500\frac{N}{m}

Since the book is released from a height h = 0.9 m above the top of the spring. so the total distance

y = h + x

Now in that case for the spring

mg y= \frac{1}{2} k x^{2}

mg(h +x) = \frac{1}{2} k x^{2}

By rearranging the above equation we get

k x^{2}  - 2mgx - 2mg h = 0

Put all the values in above equation we get

1500x^{2}  - 29.43 x - 26.48 = 0

By solving the above equation we get

x = 0.143 m= 14.3 cm

This is the value of the maximum distance the spring will be compressed.

8 0
3 years ago
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