Two men p and q set off from a base camp r prospecting for o,p moves 40km on a bearing 205 degree and q moves 30km on a bearing
of 060 degree
a. Find the distance of q from p
b. The bearing of q from p
1 answer:
Answer:
(a) By cosine rule, /PQ/2=202+152−2×20×15×cos145°
= 400+225−600cos145°
= 625+600×0.8192
= 491.52+625
/PQ/2=1116.52⟹/PQ/=1116.52−−−−−−√=33.41
≊33km ( to the nearest whole number)
(b) By sine rule,
sin<QPR15=sin14533.41
sin<QPR=15sin14533.41
sin<QPR=15×0.573633.41=0.2575
<QPR=14.92°
∴ Bearing of Q from P = 25° + 14.92° = 39.92°.
≊40° (to nearest whole number)
Step-by-step explanation:
hope it helps
...
You might be interested in
Answer:
i dont really know for sure, but try P (-8, 6) Q (-5, 2) and R (2, 1) sorry if its wrong
Step-by-step explanation:
Two right angles? that's what I would think
Answer:
4 (2 a + 3 b)
Step-by-step explanation:
Simplify the following:
8 a + 12 b
Factor 4 out of 8 a + 12 b:
Answer: 4 (2 a + 3 b)
Answer:
Where is the figure????
Don't waste your points unnecessarily. ✌✌
-2x*(-3x)-2x*(-4y)-2x*(-8)
answer :6x^2+8xy+16x