Part A
Either Nathan picked 0, or Sonia picked 0, or both.
This is because multiplying nonzero numbers together gets a nonzero result. So one of them must have picked 0.
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Part B
It's the same idea as part A. It's not clear what the nonzero values are, but one (or more) person picked 0 as their secret number.
If they picked something like 1, 2 and 3, then the product is 1*2*3 = 6 which is nonzero and the product is larger than the three original values. This is because each value is 1 or larger. If someone picked a small decimal value like 0.1 then 0.1*2*3 = 0.6 is the product. It's closer to 0, but not 0 itself.
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Part C
Zero Product Property:
If m*n = 0, then either m = 0 or n = 0 or both.
This idea says that if the product of two numbers is 0, then at least one of the numbers must be 0 itself. It can be extended to three or more numbers.
This idea is useful when it comes to solving factored quadratic equations.
In the case of 2x^2 + 5x - 12, it factors to (2x-3)(x+4)
So using the zero product property, we can solve the quadratic equation like this
2x^2 + 5x - 12 = 0
(2x-3)(x+4) = 0
2x-3 = 0 or x+4 = 0
2x = 3 or x = -4
x = 3/2 = 1.5 or x = -4
The use of the zero product property happens in step 3
Answer:
y=-2
Step-by-step explanation:
3y+2=-2+y
subtract the 1y from both sides leaving you with 2y+2=-2
Then subtract 2 from both sides leaving you with 2y=-4
Then divide by 2 on both sides leaving you with y=-2
Answer:
5.5 + 8.5 = 14
14/2=7
The average is 7
7 x 6.5 = 45.5
Average length x height = area
7 x 6.5 = 45.5
Step-by-step explanation:
Answer:
Amount in savings account = $24,000
amount put into time deposit account = $11,000
amount put into bond account = $7,000
Step-by-step explanation:
Let x be amount put into savings account, y be amount put into time deposit account and z be amount put into bond account.
Thus;
0.05x + 0.07y + 0.09z = 2600 - - (eq1)
Also,
x + y + z = 42,000 - - - (eq2)
Now,we are told she invested 6000 more in the savings account than the other 2 combined. Thus;
x = 6000 + y + z
So,
x - y - z = 6000 - - - (eq3)
Solving the 3 equations simultaneously gives;
x = $24,000 ; y = $11,000 ; z = $7,000
