Some rational numbers are not integers. Is The False Option....
Answer:
Center = (2,5)
Radius = 10
Choice A
To find this answer, first write the equation
(x-2)^2 + (y-5)^2 = 100
into
(x-2)^2 + (y-5)^2 = 10^2
Note how the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2
We see that (h,k) = (2,5) is the center
and r = 10 is the radius
The general equation of the circle is expressed as (x-h)2 + (y-k)2 = r2 where (h,k) is the center of the circle. we are are given the center of the circle at (0,0) so the expression is simplified to <span>(x)2 + (y)2 = r2. given the other point, r2 is equal to 41. hence the final equation is x2 + y2 = 41</span>
Answer:
c
Step-by-step explanation:
You had the right idea using the Pythagorean theorem to solve for b.
Problem is for that triangle to work, the 5 and the 2√2 would have to switch places. The length of a leg cannot be larger than the length of the hypotenuse for it to truly be a right triangle.
Pythagorean theorem only works for the right triangles. Only way to "solve this problem would be to bring in complex numbers.
5² + b² = (2√2)²
25 + b² = 2²(√2)²
25 + b² = 4(2)
25 + b² = 8
b² = 8 - 25
b² = - 17
b = √-17
b= (√17i)
Then the problem with THIS is a measurement/distance cannot be negative... which goes against exactly what that complex number i is.
